Pleiotropy occurs when one gene influences multiple, seemingly unrelated phenotypic traits. A single gene is responsible for pigmentation and hearing.
Answer:
Vision
Explanation:
Sensory cells may detect the information like taste, touch, hear and vision by the presence of receptors located on their surface.
Hyperpolarisation may be defined as the change in the cell's membrane potential towards more negative. The sensory vision cells are associated with the hyperpolarisation of cells and makes the cells environment more negative in response to the stimuli.
Thus, the correct answer is option (d).
Answer:
The correct answer is - 75% or 3/4.
Explanation:
In the given question, there is a cross between III-6 and III-7 that produced two double eyes monsters and expected one more. As given in the image that the A or single eye is dominant over the a or double eye then both parents must be heterozygous as they produced double eye offspring (aa) and they do have only one eye.
then chances of single eye offspring would be -
cross: Aa and Aa
gametes: A, a and A, a
Punnett square:
A a
A AA Aa
a Aa aa
so there are 75% chances to have a single eye and 25% chances for a double eye.
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
B) the amount of available resources
