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Elis [28]
3 years ago
8

What is the approximate capacity of the cube in liters? 75mm 75mm 75mm -cube

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

  0.422 L

Step-by-step explanation:

A little-used fact is that a <em>liter</em> is a <em>cubic decimeter</em>. The dimensions of your cube are ...

  edge length = 75 mm = 75/1000 m

Since a decimeter is 1/10 of a meter, we want the denominator to be 10. Moving the numerator and denominator decimal points 2 places to the left, we get ...

  edge length = 0.75/10 m = 0.75 dm

Then the volume of the cube is ...

  V = (0.75 dm)^3 = 0.422 dm^3 = 0.422 L

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15 points!!! GEOMETRY help please!!<br> Questions attached!
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3. Look at the picture.

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4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

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5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
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1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a
Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

f(x)=x^2

g(x)=|x|

It is given that,

(f\circ g)(x)=|x|^2=x^2

(g\circ f)(x)=|x^2|=x^2

According to chin rule,

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It means, (f\circ g)(c) is differentiable if f(g(c)) and g(c) is differentiable at x=c.

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3 years ago
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Triss [41]

Answer:

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Step-by-step explanation:

if you have two points from the graph then you can use them to find the slope, for example:

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you would take the first point and put it in a fraction (and the second point) but the x goes on the bottom and the y goes on the top:

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3-5/2-0

Then you solve:

-2/2

-1

which means that -1 is the slope for this

(the "/" is a fraction bar, in case you didn't already know that)

5 0
3 years ago
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