Ask question

Ask question

All categories

2 years ago

11

Chan paid $4.75 for trail mix that cost$2.50 a poud. How many pouds of trail mix dos he buy? Can you help me i do know how to so

lve this problem.

1 answer:

Tems11 [23]2 years ago

6 0

Answer: 1.9 pounds of trail mix

Step-by-step explanation:

You might be interested in

Solve equation<br>8-3(p-4)=2p

LenKa [72]

Answer:

ok the answer is: p=-4

Step-by-step explanation:

First you distribute 3 times p-4 and get 8-3p+12=2p then you add 12 plus 8 and get 20 then you have 20-3p=2p you have to add 3p on both sides and you get 20= -5p you divide and get p= -4

6 0

3 years ago

You can spend at most $20 on tomatoes and red peppers for a soup. Tomatoes cost $2.50 per pound and red peppers cost $4 per poun

Umnica [9.8K]

Answer:

The expression which represents the quantity of tomatoes and red peppers to buy is $ 2.50 × T + $ 4 × R = $ 20

Step-by-step explanation:

Given as :

The total amount spend for soup = $ 20

The cost of Tomatoes = $ 2.50 per pound

The cost of Red peppers = $ 4 per pound

Let the quantity of tomatoes to be bought = T pound

The quantity of red peppers to be bought = R pound

So, According to question

$ 2.50 × T + $ 4 × R = $ 20

I.e The expression which represents the quantity of tomatoes and red peppers to buy is $ 2.50 × T + $ 4 × R = $ 20 . Answer

5 0

3 years ago

What is the value of 9 plus 16?

liraira [26]

Answer:

25

Step-by-step explanation:

9+16=25

5 0

2 years ago

Use any method to multiply (-14ab)(a + 3b - 4c).

NeX [460]

Answer:

-14a^2b-42ab^2+56abc

Step-by-step explanation:

You can use the FOIL method

multiply the first numbers

then inner

then outer

then last

8 0

3 years ago

Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist

Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

$\frac{70}{100}\times 60=42$

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

$\frac{75}{100}\times 42=31.5$

Number of students who need help in computer science and enrolled in his class after school hours

$\frac{30}{100}\times 60=18$

Therefore, there are $31.5+18=49.5$ students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

$\frac{49.5}{60}\times 100=82.5\%$

Hence, there are 82.5% after school students who are enrolled in his classes.

6 0

3 years ago