I’d say probably a forest
Answer:
D) Van der Waals
Explanation:
Given that the geometry is linear, one finds that the C = O bonds cancel out any polar effects due to the linear geometry ( O = C = O )and gives the molecule a net dipole of zero. Interactions are therefore dependent upon dispersion forces that are classified as Van der Waal Forces or London Forces.
Answer:
5' RG GWCCY 3'
3' YCCWG GR 5'
Explanation:
The enzyme PpuMI is a restriction endonuclease enzyme, it has a specific recognition site where it cut the DNA. The source of the enzyme is from an E. coli strain that carries the PpuMI gene from Pseudomonas putida (R. Morgan).
The enzyme PpuMI recognizes specific sequence with palindrome arrangement. It target the sequence 5' RGGWCCY 3'
target Sequence: 5' RGGWCCY 3'
3' YCCWGGR 5'
The enzyme cleavage point is at:
5' RG^GWCCY 3'
3' YCCWG^GR 5'
The product of the cleavage will give a sticky end Cleavage:
5' RG GWCCY 3'
3' YCCWG GR 5'
Note: R stands for purines (adenine and guanine). Y stands for pyrimidines (cytosine, thymine, and uracil). And W represents adenine or thymine.
Answer:
Explanation:
Compounds derived from Phosphatidyl choline are referred to as Lysolecithins. These compounds are amphiphatic in nature and have both hydrophilic and hydrophobic regions.
Choline, glycerol, and phosphate represent the hydrophyilic portion of lysolecithins,while the fatty acid on C1 is hydrophobic in nature.
Glycerol, choline and phosphate act as a polar tail whereas the fatty acid acts as a long polar head which represents an amphipathic molecule like detergents.
Answer:
n = 1.3 x 10¹⁸ photons
Explanation:
First we need to calculate the amount of energy released in given time:
E = Pt
where,
E = Energy = ?
P = Power = 4 mW = 0.004 W
t = time = 115 s
Therefore,
E = (0.004 W)(115 s)
E = 0.46 J
Now, this energy can be given in forms of photons as:
E = nhc/λ
where,
n = No. of photons = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light = 5650 x 10⁻¹⁰ m
Therefore,
0.46 J = n(6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(5650 x 10⁻¹⁰ m)
n = (0.46 J)/(3.5 x 10⁻¹⁹ J)
<u>n = 1.3 x 10¹⁸ photons</u>
