3 L will be the final volume for the gas as per Charle's law.
Answer:
Explanation:
The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.
V∝ T
Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be
![\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%20%7D%7BT_%7B1%7D%20%7D%3D%20%5Cfrac%7BV_%7B2%7D%20%7D%7BT_%7B2%7D%20%7D)
So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.
![\frac{6}{80}=\frac{V_{2} }{40}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B80%7D%3D%5Cfrac%7BV_%7B2%7D%20%7D%7B40%7D)
![V_{2}=\frac{6*40}{80}=3 L](https://tex.z-dn.net/?f=V_%7B2%7D%3D%5Cfrac%7B6%2A40%7D%7B80%7D%3D3%20L)
So, 3 L will be the final volume for the gas as per Charle's law.
Your answer is C forms of the same element that differ in the number of neutrons in each atom because if the number of neutrons change the whole element changes.
Answer:
- last option: none of<u> the above.</u>
Explanation:
Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.
One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.
On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.
A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.
From above, there is no way that you can conclude whether a solution is supersaturated or not from the statement that a solution is concentrated, so the answer is<u> none of the above</u>.
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