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3 years ago

14

What is it called when evaporation takes place beneath the surface of a liquid

1 answer:

Tems11 [23]3 years ago

5 0

It is called boiling when evaporation takes place beneath the surface of a liquid. The evaporation is a kind of vaporization only takes place at the surface of a liquid.

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In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made

LenKa [72]

The correct option is C. The amount of MgCl2. we know this because <span>no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you</span>

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3 years ago

Please help mee 11-14

Artemon [7]

Answer:

11. A)outward

12. B) inward

13. B) opaque

14. I really don't know (sorry)

Explanation:

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3 years ago

If a piece of matter changes shape, how does its mass change?

kap26 [50]

The law of conservation of mass states that matter cannot be created nor destroyed the answer would be D. It remains the same

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3 years ago

The half life of an isotope X is 3 days how long will it take for 1/2 of a 10 G sample to decay

lorasvet [3.4K]

Answer: It will take 3 days for half of a 10 g sample to decay.

Explanation:

Half-life of sample of an isotope X = 3 days

$\lambda=\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{3 days}=0.231 day^{-1}$

$N=N_o\times e^{-\lambda t}$

$\lnN=-\lambda t\lnN_o$

Sample decayed = $\frac{N_o}{2}=\frac{10 g}{2 g}=5 g$

N= $N^o-\text{sample decayed}=10 g-5 g=5 g$ , time = t

$\ln[5 g]=-0.231 day^{-1}\times t\ln[10]$

$\ln[\frac{5}{10}]=-0.231\times t$

$\ln\frac{1}{2}=-0.693=-0.231\times t$

t = 3 days

It will take 3 days for half of a 10 g sample to decay.

3 0

3 years ago

Using only the periodic table, write the symbol of the ion most typically formed by each of the

ahrayia [7]

Answer:

The ion is written in the attached file

Explanation:

3 0

3 years ago