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2 years ago

14

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

.

1 answer:

Georgia [21]2 years ago

7 0

Answer:

i feel like correct answrr would be C. Hope this helps!!!

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How are √25 and √-25 different in the terms of a solution for both? *

Tanya [424]

Answer:

For $\sqrt{25}$ it will be plus or minus $\sqrt{5}$

For $\sqrt{-25}$ it will be plus or minus $\sqrt{5i}$

Step-by-step explanation:

Well for $\sqrt{-25}$ it will be 5i

Because i = -1

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3 years ago

31<br>Write as a mixed number.<br>Give your answer in its simplest form.

makvit [3.9K]

Six divided by five maybe and add a 1

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2 years ago

Consider the baggage check-in process of a small airline. Check-in data indicates that from 9am to 10am, 220 passengers checked

Lady bird [3.3K]

Answer:

3.6 minutes.

Step-by-step explanation:

According to the data given in the question, between 9 and 10 AM, 220 passengers have checked in which means that the check-in rate is 3.6 passengers per minute. If the average number of passengers waiting for check-in is 32 and if we assume that the check-in rate is constant throughout the day, then the average passenger had to wait in line for 3.6 minutes.

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3 years ago

How to find out L C M of common division method

stealth61 [152]

$\huge\bigstar\:$ $\Huge\tt\underline\blue{ANSWER}$

To find Least Common Multiple by using Division Method we need to follow the following steps.

Step 1: Write the given numbers in a horizontal line, separating them by commas.

Step 2: Divide them by a suitable prime number, which exactly divides at least two of the given numbers.

<h3>HOPE IT HELPS YOU...</h3>

4 0

3 years ago

Read 2 more answers

A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres

VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

$x^{1} *(x-4)^{3}$ becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

$x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x$

8 0

2 years ago