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3 years ago

Calculate the force on an object that has a mass of 12kg and an acceleration of 4m/s2

Physics

1 answer:

Gwar [14]3 years ago

6 0

<span> Force = mass x acceleration. </span>

<span>Force = 12 kg x 4 m/s2 = 48 kgm/s2 = 48 Newtons</span>

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A charge of +2 C is at the origin. When charge Q is placed at 2 m along the positive x axis, the electric field at 2 m along the

sveticcg [70]

Answer:

The value of Q is - 8 C

Explanation:

Given;

the magnitude of first charge = 2 C

position of the first charge = 0

_ (2m) 0(+2C) +(2m)(Q)

------------------------------------------------------------------------------------

E₁ --------------------------------->

<------------------------------------------------------------------ E₂

E₁ and E₂ are equal in magnitude but opposite in direction

| E₂ | = | E₁ |

$\frac{K*Q}{r^2} = \frac{K*2}{r^2} \\\\\frac{Q}{(4)^2} = \frac{2}{(2)^2}\\\\\frac{Q}{16} =\frac{2}{4}\\\\\frac{Q}{16} =\frac{1}{2}\\\\2Q = 16\\\\Q = 8 \ C$

Thus, since E₂ is opposite in direction to E₁, the Q = - 8 C

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4 years ago

Which of the following air conditions would be least likely to have precipitation? A. warm, dry air B. warm, moist air C. cold,

hram777 [196]

Answer:

Explanation:

when it's cold,the water vapour that atmosphere can hold is much lower....and when moist air have so much water vapour in it...perfect condition for precipitation

8 0

3 years ago

Position can best be described as

Elan Coil [88]

B. The location of an object.

The term position describes the location of a place with respect to some reference point called origin.

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4 years ago

A mass of 2 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 20 N/m, and the s

Sergio [31]

The speed of the mass : <em><u>v = 0.316 m/s</u></em>

<h3>Further explanation</h3>

The energy used to press a spring is included as the potential energy

Can be formulated:

$\displaystyle E_p=\frac{1}{2}kx^2$

Ep= potential energy

k = spring constant

x = change in spring length

If the spring is released from its pressure, this potential energy will turn into kinetic energy

so applies the law of conservation of mechanical energy (Em)

Ek = Ep

A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.

m = 2 kg

k = 20 N/m

x = 0.1 m

$\displaystyle Ep=Ek\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\kx^2=mv^2\\\\20\times0.1^2=2\times v^2\\\\v^2=0.1\\\\v=\sqrt{0.1}\\\\v=0.316~m/s$

<h3>Learn more</h3>

Hooke's law

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Keywords : spring,mass, spring constant,compressed position

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3 years ago

Light described as what two things?

seraphim [82]

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

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3 years ago