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rewona [7]
3 years ago
8

What is a true statement about the rotation period of the moon?

Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0
The time it takes for the Moon to rotate once around its axis is equal to the time it takes for the Moon to orbit once around Earth
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What is the definition of a point object?
Kaylis [27]
Point object is an expression that is used in Kinematics. It refers the object whose dimensions are ignored or neglected and is treated as a dot object to simplify the calculations. When the object is treated as a point object it means the whole mass is summed in one point, you can imagine it as a sphere which has the mass and the radius is 0...
4 0
3 years ago
An object 20cm high is placed at a distance of 100 cm from a plane mirror. The height of the image will be.
Mandarinka [93]
B) 20 cm


The height and distance will be the same. Only the image will be laterally inverted.
6 0
2 years ago
A bullet is shot vertically upward with an initial velocity of 128 ft/s. The bullet's height after t seconds is y(t) = 128t - 16
saul85 [17]

The height of the bullet when the velocity is zero is 256 ft.

<h3>Height of the bullet when the velocity is zero </h3>

The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

v = \frac{dy}{dt} = 128 -32t \\\\when \ v \ is \ zero\\\\v = 0\\\\128 - 32t = 0\\\\32t = 128\\\\t = \frac{128}{32} \\\\t = 4 \  s

The height of the bullet at this time is calculated as follows;

y(4) = 128(4) - 16(4)^2\\\\y(4) = 256 \ ft

Learn more about height of projectiles here: brainly.com/question/10008919

6 0
2 years ago
What must be the distance in meters between point charge q1 = 23.5 µc and point charge q2 = -64.2 µc for the electrostatic force
svlad2 [7]
The answer for your problem is shown on the picture.

7 0
3 years ago
A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c
Anna35 [415]

The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

4 0
2 years ago
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