Answer:
0.2 m
Explanation:
magnetic force = centripetal force
qvB = mv² / r
cancel v on both side and make r subject of the formula
r₁ = mv / qB where m = mass of ion, v = velocity of the ion
r₁ = ( 235 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T) = 1139.24 × 10⁻² = 11.4 m
r₂ = ( 238 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T) = 1153.78 × 10⁻² = 11.5 m
D, distance between the impact points formed = d₂ - d₁ where d₂ and d₁ represent the diameters of the charged ions
D = (2 × 11.5 m) - ( 2 × 11.4) = 2 ( 11.5 - 11.4) = 0.2 m
5,625 x 10 ⁻¹⁰ is <span>the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters.</span>
Answer:
mass multiplied by velocity (4 words but uh
Answer:
8.46E+1
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 39 C
Charge 2 (q₂) = –53 C
Force (F) of attraction = 26×10⁸ N
Electrical constant K) = 9×10⁹ Nm²/C²
Distance apart (r) =?
The distance between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
26×10⁸ = 9×10⁹ × 39 × 53 / r²
26×10⁸ = 1.8603×10¹³ / r²
Cross multiply
26×10⁸ × r² = 1.8603×10¹³
Divide both side by 26×10⁸
r² = 1.8603×10¹³ / 26×10⁸
r² = 7155
Take the square root of both side
r = √7155
r = 84.6 m
r = 8.46E+1 m
Hence the expression of ω in terms of m and k is
Given the expressions;
Equating both expressions we will have;
Divide both equations by 2π
Square both sides
Take the square root of both sides
Hence the expression of ω in terms of m and k is
