A. 1.35 is the number in between 1.2 and 1.5.
Principles of conservation of linear momentum
Kinetic Energy before collision 60kJ
Kinetic Energy after collision 56.76kJ
Explanation:
1. Given data
mass m1= 1000kg
velocity u1= 10m/s
mass m2= 800kg
velocity u2= 5m/s
2. We want to find the common velocity after the collision
Applying the principle of conservation of linear momentum for inelastic collision we have
m1u1+m2u2= (m1+m2)V
substituting and solving for V
1000*10+800*5= (1000+800)V
10000+4000= 1800V
14000=1800V
3. Divide both sides by 1800
V= 14000/1800
V= 7.8m/s
4. Now let us find the kinetic energy of the two cars before the collision
For the first car
KE= 1/2m1u1^2
KE= 1/2*1000*10^2
KE=(1000*100)/2
KE= 100000/2
KE= 50000 Joules
KE= 50 kJ
For the second car
KE= 1/2m2u2^2
KE= 1/2*800*5^2
KE=(800*25)/2
KE= 20000/2
KE= 10000 Joules
KE= 10 kJ
Hence the total kinetic energy before the collision is
=50+10
=60kJ
After collision
KE= 1/2m1V^2
KE= 1/2*1000*7.8^2
KE=(1000*60.84)/2
KE= 60840/2
KE= 32420 Joules
KE= 32.42kJ
For the second car
KE= 1/2m2u^2
KE= 1/2*800*7.8^2
KE=(800*60.84)/2
KE= 48.672/2
KE= 24336 Joules
KE= 24.34 kJ
Hence the total Kinetic energy after collision is
=32.42+24.34
=56.76kJ
See the link below for more information on linear momemtum
https://brainly.in/question/17792506
Answer: x = 0.957 m
Explanation:
F = ma
d = ½at²
a = 2d/t²
F = m2d/t²
F = kx
kx = m2d/t²
x = 2md/kt²
x = 2(8.86)(4.36) / (471(0.414²))
x = 0.957036...
Answer:
A) 1.9m/s
Explanation:
Use the equation v=d/t
The time is 10 seconds. The distance is more complicated because it’s a circle so u use the equation for circumference C=2•pi•r. So you just do the circumference over time and get the answer. Hope this helps
An electromagnet is only magnetic when there's electric current flowing through its coils <em>(A)</em>. When there's no current flowing through it, it just lays there like a lump of iron with wire wound around it.