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GREYUIT [131]
3 years ago
12

In 0.414 s, a 8.86-kg block is pulled through a distance of 4.36 m on a frictionless horizontal surface, starting from rest. The

block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 471 N/m. By how much does the spring stretch
Physics
1 answer:
Lena [83]3 years ago
3 0

Answer: x = 0.957 m

Explanation:

F = ma

d = ½at²

a = 2d/t²

F = m2d/t²

F = kx

kx = m2d/t²

x = 2md/kt²

x = 2(8.86)(4.36) / (471(0.414²))

x = 0.957036...

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