Givens.
• 14.91 meters North.
,
• 4.40 meters East.
First, make a diagram to visualize the vectors and the resultant displacement.
In the figure, the purple vector d represents the resultant displacement, which horizontal component is 4.40m and its vertical component is 14.91m.
Let's use the following formula to find the resultant.
Where y = 14.91 and x = 4.40.
Therefore, the magnitude of the resultant displacement is 15.55m.
But, the resultant displacement refers to the vector, which is the following
We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s²
d = ut + 1/2 at²
6.0 = 0 + (1/2 × 9.80 t²)
t = √(12/9.8)
= 1.106 sec
Horizontal velocity = Vh = Dh/t
= 24.0 /1.106 s
= 21.69 m/s
The ball was thrown at a speed of 21.69 m/s
Answer:
D) Fusion requires high temperatures and pressures, so how have they reduced the energy cost for it?
Explanation:
Fusion requires high temperatures and pressure for initiation of reaction . There is no chain reaction in it so there is no problem of controlling the problem . On the other hand , the reaction tends to stop as soon as temperature goes down due to heat getting dissipated . There is no problem of fuel as its fuel is deuterium which is present in nature in large amount . The question which is pertinent is that the cost involved in attaining so high temperature is very high so is it cost effective to produce energy by incurring so much of cost . Producing energy by using so much of energy in the beginning appears to be preposterous.
Answer:
q₁ / q₂ = 4
Explanation:
In this exercise we must use Coulomb's law
F = k q₁q₂ / r²
For this case the electric force is
F = k q₁ Q / r₁²
indicate that another particle q₂ has the same force on Q, but for r₂ = r₁ /2
F = k q₂ Q / r₂²
we equate the two equations
q₁Q / r₁² = q₂ Q / r₂²
we substitute r₂
q₁Q / r₁² = q₂ Q / (r₁/2)²
q₁ = q₂ 4
the relationship between the two charges is
q₁ / q₂ = 4
I don't know Ioput, <span>but :
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gravity is:
simplified to near surface force:
so :
M mass of planet
R radius of planet
G gravitational constant