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GREYUIT [131]
2 years ago
12

In 0.414 s, a 8.86-kg block is pulled through a distance of 4.36 m on a frictionless horizontal surface, starting from rest. The

block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 471 N/m. By how much does the spring stretch
Physics
1 answer:
Lena [83]2 years ago
3 0

Answer: x = 0.957 m

Explanation:

F = ma

d = ½at²

a = 2d/t²

F = m2d/t²

F = kx

kx = m2d/t²

x = 2md/kt²

x = 2(8.86)(4.36) / (471(0.414²))

x = 0.957036...

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2 years ago
A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a
sattari [20]

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16 km

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Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

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5 0
3 years ago
Radio waves travel at the speed of light, which is 3.00 u 108 m/s. How many kilometers will radio messages travel in exactly one
egoroff_w [7]

Answer:                

Distance traveled will be 9.462\times 10^{12}km

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So 9.462\times 10^{15}m=\frac{9.462\times 10^{15}}{1000}=9.462\times 10^{12}km

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