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olchik [2.2K]
3 years ago
13

Please helpp!

Physics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

a. 1 Newton = 100000 Dyne

b. a represents acceleration.

Explanation:

Newton is the standard unit (S.I) of measurement of force. Converting 1 Newton to dyne we have;

1 Newton = 10⁵ Dyne

1 Newton = 100000 Dyne

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

F = ma

Hence, we can deduce that a represents the acceleration of an object and it's measured in meters per seconds square.

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ANSWER ASAP AND WILL GIVE BRAINLIEST AND POINTS
denis-greek [22]

Answer:

D

Explanation:

Mars is the planet between Earth and Jupiter, or the 4th planet from the Sun.

8 0
3 years ago
Read 2 more answers
Why is the law of gravity an example of a universal law? a Gravity is the attraction of any mass to any other mass. b Gravity is
konstantin123 [22]
D and A are quite the same, but I think D is more general.
3 0
3 years ago
Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec​
Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Solving for f:

\displaystyle f=\frac{\omega}{2\pi}

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\displaystyle \omega=\frac{25}{90}

\displaystyle \omega=0.278\ rad/s

Now we calculate f:

\displaystyle f=\frac{0.278}{2\pi}

f=0.04421\ Hz

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0
3 years ago
An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow.
laila [671]

Answer:

300 N

Explanation:

The net force acting on the arrow is given by Newton's Second Law:

F=ma

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

F=(0.06 kg)(5,000 m/s^2)=300 N

7 0
4 years ago
Please help me i need some help!!!
Montano1993 [528]

Answer:

D on first page

I think on the second page is also D

The third page is B

Explanation:

5 0
3 years ago
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