Ask question

Ask question

All categories

2 years ago

7

How do we determine the age of rocks and other geologic features?

1 answer:

Mamont248 [21]2 years ago

4 0

Answer:To establish the age of a rock or a fossil, researchers use some type of clock to determine the date it was formed. Geologists commonly use radiometric dating methods, based on the natural radioactive decay of certain elements such as potassium and carbon, as reliable clocks to date ancient events.

Explanation:

You might be interested in

A change in which of the following effects the weight of an object?

Masja [62]

Acceleration due to gravity

4 0

3 years ago

What type of wave does not need matter to carry energy?

marishachu [46]

Non- mechanical wave does not need matter to carry energy.

e.g:- Light

3 0

3 years ago

Read 2 more answers

2. A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is

mash [69]

Answer:

$6.38\cdot 10^6 m$

Explanation:

The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

$I=\frac{2}{5}MR^2$

where

M is the mass

R is the radius

For the planet in the problem, we have

$M=5.98\cdot 10^{24} kg$

$I=9.74\cdot 10^{37} kg\cdot m^2$

Solving the equation for R, we find the radius of the planet:

$R=\sqrt{\frac{5I}{2M}}=\sqrt{\frac{5(9.74\cdot 10^{37}}{2(5.98\cdot 10^{24}}}=6.38\cdot 10^6 m$

3 0

2 years ago

1. What happens to particle spacing when temperature increase, What we call this process?

enot [183]

Answer:

Particle spacing increases and it's called evaporating

5 0

3 years ago

A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed v = 0.80c rel

hjlf

To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

Where

$l_0$ = Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-0.8^2}$

$l = 7.2*10^{10}m$

Therefore the distance between Mars and Venus measured by the Martin is $7.2*10^{10}m$

8 0

2 years ago