The table shows the population density for the state of Texas in various years. Find the average annual rate of change in the po
pulation density from 1960 to 2000. Do NOT round your answer.
The population density increased by about _________ people per square mile.
1 answer:
Answer:
The population density increased by about 1.08 people per square mile.
Step-by-step explanation:
![\mathbf{Average \ annual \ rate \ of \ change \ in \ population \ density =\frac{Change \ in \ population \ in \ density}{Total \ number \ of \ years}}](https://tex.z-dn.net/?f=%5Cmathbf%7BAverage%20%5C%20annual%20%5C%20rate%20%5C%20of%20%5C%20change%20%5C%20in%20%5C%20population%20%5C%20density%20%3D%5Cfrac%7BChange%20%5C%20in%20%5C%20population%20%5C%20in%20%5C%20density%7D%7BTotal%20%5C%20number%20%5C%20of%20%5C%20years%7D%7D)
Population in year 1960 is 36.4 people per square mile.
Population in year 2000 is 79.6 people per square mile.
Change in population density between year 1960 and 2000 is:
79.6 - 36.4 = 43.2
Total number of year between year 1960 and 2000 is:
2000 - 1960 = 40
Substituting the values in above formula:
![\textrm{Average annual rate of change in population density}=\frac{79.6-36.4}{2000-1960}](https://tex.z-dn.net/?f=%5Ctextrm%7BAverage%20annual%20rate%20of%20change%20in%20population%20density%7D%3D%5Cfrac%7B79.6-36.4%7D%7B2000-1960%7D)
![\textrm{Average annual rate of change in population density}=\frac{43.2}{40}](https://tex.z-dn.net/?f=%5Ctextrm%7BAverage%20annual%20rate%20of%20change%20in%20population%20density%7D%3D%5Cfrac%7B43.2%7D%7B40%7D)
![\therefore\mathbf{Average \ annual \ rate \ of \ change \ in \ population \ density=1.08}](https://tex.z-dn.net/?f=%5Ctherefore%5Cmathbf%7BAverage%20%5C%20annual%20%5C%20rate%20%5C%20of%20%5C%20change%20%5C%20in%20%5C%20population%20%5C%20density%3D1.08%7D)
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