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2 years ago

Classify each of these reactions pb(no3)2+nicl2=pbcl2+ni(no3)2

Chemistry

1 answer:

maxonik [38]2 years ago

4 0

The reaction Pb(NO3)2(aq) + NiCl2(aq)---------> PbCl2(s) + Ni(NO3)2(aq) is a precipitation reaction.

A chemical reaction is said to occur when two or more substances are combined to produce new substances. Chemical reactions are classified based on the kind of change taking place in the reaction.

In the reaction;

Pb(NO3)2(aq) + NiCl2(aq)---------> PbCl2(s) + Ni(NO3)2(aq)

We can see that a solid is formed when lead II nitrate reacts with nickel II chloride. This is a precipitation reaction.

Learn more: brainly.com/question/5624100

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What are the subatomic particles of barium

ivolga24 [154]

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2 years ago

Please help with #2 and #3

Vaselesa [24]

Answer:

2. $V_2=17L$

3. $V=82.9L$

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

$\frac{V_2}{T_2}=\frac{V_1}{T_1}$

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

$V_2=\frac{V_1T_2}{T_1}$

Therefore, we plug in the given data to obtain:

$V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L$

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

$V=\frac{nRT}{P}$

Therefore, we plug in the data to obtain:

$V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L$

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6 0

2 years ago

An amphoteric species is neither an acid nor a base. True or False

umka2103 [35]

Answer: False

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2 years ago

At the end of mitosis the cells produced are identical to each other is it True or False

My name is Ann [436]

True:

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2 years ago

How many of grams of CuSO4 are in 475ml of a 2.0M aqueous solution

Anettt [7]

Answer:

151.63 g

Explanation:

We first get the number of moles;

Moles = Molarity × volume

= 2.0 × 0.475

= 0.95 moles

1 mole of CuSO4 = 159.609 g/mol

Therefore;

Mass = moles × molar mas

= 0.95 moles × 159.609 g/mol

= 151.63 g

8 0

3 years ago

Read 2 more answers