Answer:
2,3–dimethylpentane
Explanation:
To know which option is correct, we shall determine the name of the compound.
To obtain the name of the compound, do the following:
1. Determine the longest continuous carbon chain. This gives the parent name of the compound.
2. Identify the substituent group attached to the compound.
3. Locate the position of the substituent group by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, we shall determine the name of the compound as follow:
1. The longest continuous carbon chain is 5. Thus, the parent name of the compound is pentane.
2. The substituent group attached is methyl (–CH₃)
3. There are two methyl group attached to the compound. One is located at carbon 2 and the other at carbon 3.
4. Therefore, the name of the compound is:
2,3–dimethylpentane
None of the options are correct.
The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.
The solution is as follows:
K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106
The molar mass of isoborneol/borneol is 154.25 g/mol
Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol
Use the ICE approach
borneol → isoborneol
I 0.0972 0.0486
C -x +x
E 0.0972 - x 0.0486 + x
Total moles = 0.1458
Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P
0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832
Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
