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2 years ago

Y=4x+5 has a gradient of 4 what is the equation of aline parallel to it?

Mathematics

2 answers:

Aloiza [94]2 years ago

8 0

Your answer is Y= 4x + 2

marysya [2.9K]2 years ago

7 0

A line parallel to it will have the same gradient (slope) of 4, but a different y int.

so a line parallel to it could be :
y = 4x + 3....or y = 4x + 4, or y = 4x + 5......that last number, ur y intercept, can be anything but 5

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11.5.5

Umnica [9.8K]

Answer:

Step-by-step explanation:

8 0

3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago

None of the answers here are helpful. Please help me...

ycow [4]

Answer:

The ball will strike the ground at time t = 21sec .

3 0

2 years ago

Karen purchased 18 bag of “colorful” pebbles to decorate her garden. The 18 bags had a total of 4,356 pebbles. How many pebbles

adoni [48]

Answer:

4,356 divided by 18 is equal to 242 pebbles in each bag.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If the triangles are similar, what is the value of x?

Yuri [45]

9514 1404 393

Answer:

5/9
17/90
12/45
19/66

Step-by-step explanation:

You can do these conversions the way shown in your attachment:

2) x = 0.18_8

10x = 1.88_8

9x = 1.88_8 -0.18_1 = 1.7

x = 1.7/9 = 17/90

Or, you can recognize that 0.88_8 is 8/9, but 0.088_8 is that value divided by 10: 8/90. Then 0.18_8 is 0.1 + 0.088_8 = 1/10 + 8/90 = (9+8)/90 = 17/90

Here are the others:

1) 0.5_5 = 5/9

3) 0.26_6 = 1/5 + 6/90 = (18 +6)/90 = 24/90 = 12/45

4) 0.287_87 = 1/5 + 87/990 = (198+87)/990 = 19/66

_____

<em>Further development</em>

You have probably figured out that a 1-digit repeat that starts at the decimal point is expressed as a fraction with that digit divided by 9.

x = 0.dd_d

10x d.dd_d

9x = d

x = d/9 . . . . . . for any single-digit repeat

Now doubt, you're used to seeing 1/3 = 0.33_3 = 3/9, and 2/3 = 0.66_6 = 6/9.

Similarly, a 2-digit repeat is the fraction with those two digits divided by 99 (an equal number of 9s). This holds for all n-digit repeats. The "raw" divisor is 10^n -1. In many cases, the fraction can be reduced, as in ...

0.142857_142857 = 142857/999999 = 1/7

When the repeating part of the decimal does not start at the decimal point, then the divisor (some number of 9s) must be adjusted by an appropriate power of 10. The non-repeating part can be expressed as a fraction in the usual way, then added to the value of the repeating part. Or, you can do the several-step process you show. Both work just fine.

_____

<em>About notation</em>

Overbars are difficult to show in plain text. Not all methods of creating overbars are rendered properly in documents that show plain text. In typeset text, they are used to show the repeating digits. So, other methods are sometimes used in plain text to show the repeating digits. Here are a few:

0.166_6 . . . . shows the 6 repeats

0.16(6) . . . . . shows the 6 repeats [this notation is also used to indicate error limits for the number, so can be ambiguous]

0.16... (repeating 6) . . . . . shows the 6 repeats

6 0

2 years ago