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algol13
3 years ago
8

Y=4x+5 has a gradient of 4 what is the equation of aline parallel to it?

Mathematics
2 answers:
Aloiza [94]3 years ago
8 0
Your answer is Y= 4x + 2
marysya [2.9K]3 years ago
7 0
A line parallel to it will have the same gradient (slope) of 4, but a different y int.

so a line parallel to it could be :
y = 4x + 3....or y = 4x + 4, or y = 4x + 5......that last number, ur y intercept, can be anything but 5
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3 years ago
Substitution again help please
Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\

4)

\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21

8 0
2 years ago
Question 25
AysviL [449]

Answer:

120

Step-by-step explanation:

First, you have to calculate the money that Seth would spent if he goes to 30 movies if his father gets the summer movie pass by adding up the cost of the pass plus the result of multiplying the cost per movie with the pass for the number of movies:

30+(3*30)=30+90=120

Second, you need to calculate the money that Seth would spent if he goes to 30 movies without the pass by multiplying the normal price per movie for the number of movies:

8*30=240

Third, you need to find the difference between both costs:

240-120=120

According to this, the answer is that if Seth plans to go to 30 movies this summer, he would save 120.

8 0
3 years ago
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