Moles of NaN3 at STP = volume of gas / 22.4 = 11.5/22.4 = 0.5mole. Massof NaN3 = moles of NaN3 x molecular weight = 0.5 x 65 = 32.5 grams.
As we know that
P.E. = mgh
where,
P.E. = Potential energy of the object =?
m= mass of object= 3kg
g= acceleration due to gravity = 9.8 ms^-2
h = height between object and animal = 0 m
Then
P.E. = 3× 9.8 × 0 = 0 Joules or 0J
<em>Have a luvely day!</em>
Answer:
606 atoms
Explanation:
Add the numbers 145 + 293 + 168
Answer:
In the attached photo.
Explanation:
Hello,
You could find the structure in the attached photo, taking into account that the initial (Z) resembles to the trans arrangement for this alkene.
Best regards.
Answer:
, ![\Delta P = 60.313\,W](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%2060.313%5C%2CW)
Explanation:
The change in energy is given by the change in gravitational potential energy:
![\Delta E = m\cdot g \cdot \Delta h](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20m%5Ccdot%20g%20%5Ccdot%20%5CDelta%20h)
![\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20%2882%5C%2Ckg%29%5Ccdot%20%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%5Ccdot%20%28540%5C%2Cm%29)
![\Delta E = 434253.96\,J](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20434253.96%5C%2CJ)
The average rate of change in terms of time is approximately this:
![\Delta P = \frac{\Delta E}{\Delta t}](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20%5Cfrac%7B%5CDelta%20E%7D%7B%5CDelta%20t%7D)
![\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20%5Cfrac%7B434253.96%5C%2CJ%7D%7B%282%5C%2Ch%29%5Ccdot%20%28%5Cfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%20%29%7D)
![\Delta P = 60.313\,W](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%2060.313%5C%2CW)