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____ [38]
2 years ago
12

What is the value of 1 over 2 x+3.4y when x=3 and y = 4?​

Mathematics
1 answer:
gavmur [86]2 years ago
8 0

Answer:

The value of the given expression is 27.1

Step-by-step explanation:

We are given an expression of two variable x and y.

We need to find the value of expression at x = 3 and y = 4

So first put x = 3 and y = 4 into expression and simplify

1/2 x 3 (3) + 3.4 x 4

➡️ 1/2 x 27 + 13.6

➡️ 27/2 + 13.6

➡️ 13.5 + 13.6

Now, add both of the numbers together. ( as an addition problem)

Therefore, when you ad the 2 together, you get the total of 27.1

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Suppose 20 students delegates will attend the conference. Each school should be represented fairly in relation to it's populatio
algol [13]

Answer:

To find out the number coming from each school, you need to use the proportion of the school's population out of the population of all three.

Total population = 618 + 378 + 204

= 1,200 students

North Middle school:

= 618/1,200 * 20

= 10 students

Central Middle School:

= 378 / 1,200 * 20

= 6 students

South Middle School:

= 204/1,200 * 20

= 4 students

7 0
2 years ago
2{ 5[12+5 (500 - 100)+399]}
notsponge [240]

This is solved by breaking the equasion down.

2 { 5 [12 + 5 (500 - 100) + 399 ]}

2 { 5 [12 + 5 (400) + 399]}

2 { 5 [12 + 2000 + 399]}

2 { 5 [2411]}

2 {12055}

24110

Is this the answer you were looking for?

3 0
3 years ago
Read 2 more answers
A pumpkin is launched directly upwards at 72 feet per second from a platform 12 feet high. The pumpkin's height, h, at time t se
Illusion [34]

Answer:

93 feet

Step-by-step explanation:

Let us first find the time it takes to reach the maximum height. We can do this by differentiating the height function to get velocity:

dh(t)/dt = v(t) = -32t + 72

The maximum height will occur when the velocity becomes 0. Therefore, the time it takes to reach maximum height is:

0 = -32t + 72

32t = 72

t = 72/32 = 2.25 seconds

Therefore, the maximum height of the pumpkin is:

h(2.25) = -16(2.25)^2 + 72(2.25) + 12

h(2.25) = -81 + 162 + 12

h = 93 feet

4 0
3 years ago
The sign says that the price marked on all music equipment is 30% off the regional price you buy an electric guitar for the sale
kolezko [41]
I NEED 5PT but the answer 95 and 1/2 i think
8 0
3 years ago
Read 2 more answers
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
2 years ago
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