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yarga [219]
2 years ago
6

Giardiasis is an intestinal parasite that can transmitted through person-to-person contact and infested swimming pools. This par

asite is best classified as
nosocomial.

inherited.

contagious.

iatrogenic.

asymptomatic.
Chemistry
1 answer:
Volgvan2 years ago
3 0

Answer:

I think it would be Contagious.

Explanation:

You get it from another person or from food and thats contagious.

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Nitric oxide reacts with chlorine to form nocl. the data refer to 298 k. 2no(g) + cl2(g) → 2nocl(g) substance: no(g) cl2(g) nocl
tigry1 [53]

Answer:

- 10.555 kJ/mol.

Explanation:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

Where, ∆G°rxn is the standard free energy change of the reaction (J/mol).

∆H°rxn is the standard enthalpy change of the reaction (J/mol).

T is the temperature of the reaction (K).

∆S°rxn is the standard entorpy change of the reaction (J/mol.K).

  • Calculating ∆H°rxn:

∵ ∆H°rxn = ∑∆H°products - ∑∆H°reactants

<em>∴ ∆H°rxn = (2 x ∆H°f NOCl) - (1 x ∆H°f Cl₂) - (2 x ∆H°f NO) </em>= (2 x 51.71 kJ/mol) - (1 x 0) - (2 x 90.29 kJ/mol) = - 77.16 kJ/mol.

  • Calculating ∆S°rxn:

∵  ∆S°rxn = ∑∆S°products - ∑∆S°reactants

<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>

<em></em>

  • Calculating ∆G°rxn:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>

4 0
3 years ago
Substances that are likely to disassociate in water
mr_godi [17]

Answer:

sugar,dirt,spit

Explanation:

5 0
3 years ago
Most plants and all animals depend on _____ to meet their need for nitrogen.
kirill115 [55]
They depend on nitrogen-fixing bacteria, which convert atmospheric nitrogen into a usable form.
3 0
3 years ago
Read 2 more answers
What sequence of enzymes allows for the synthesis of glycogen from glucose-6-phosphate?
Nutka1998 [239]

Answer:

The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.

Explanation:

Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.

UDP-glucose pyrophosphorylase:  Form UDP-glucose from glucose-1-phosphate.

Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.

Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.

4 0
2 years ago
240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an
ivolga24 [154]
The answer for this would be 69.6
3 0
3 years ago
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