The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of
- height, h = apothem of the hexagon = 2 cm and
- base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>
So, the area of this triangle is A = 1/2bh
= 1/2 × 1. 5 cm × 2 cm
= 1.5 cm × 1 cm
= 1.5 cm²
<h3>Area of the hexagon</h3>
Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A
= 6 × 1.5 cm²
= 9.0 cm²
So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Learn more about area of a hexagon here:
brainly.com/question/369332
Answer:
Yes.
Step-by-step explanation:
2/12 can be reduced to 1/6
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Answer:
Area of ellipse is ≈ 77.78 
Step-by-step explanation:
Given the dimension of ellipse
a = 4.5 m
b = 5.5 m
Now, Area of ellipse = 
= 
= 
= 77.78
Hence Area of ellipse will be 77.78
Answer:×¹ = -4, ײ = -2, ׳ = 1, ×⁴ = 3
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Step-by-step explanation:
Hope this helps :)
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