Answer:
A comet
Explanation:
The picture is of an elliptical orbit of a comet. You can tell it is a comet because of the tail. Also, I just took the test and it was a comet.
Answer:
i. The pressure of due to the water, <em>P</em>, is given according to the following equation;
P = ρ·g·h
Where;
ρ = The density of the water (a constant) = 997 kg/m³
g = The acceleration due to gravity = 9.81 m/s²
h = The height of the water (minimum h = h₁, maximum h = h₂)
The pressure is directly proportional to the water height, and we have;
The pressure, <em>P</em>, will be maximum when the water height, <em>h</em>, is maximum or h = h₂, which is the level DC
ii. The thrust = The force acting on the body = Pressure × Area
The maximum areas exposed to the water are on side AB and DC
However, the pressure at level DC, which is the location of the maximum pressure, is larger than the pressure at level AB, therefore, the maximum thrust will be at the level DC
Explanation:
Only the masses of the objects and the distance between them. Nothing else affects the gravitational forces. Not even a concrete, steel, and Kryptonite wall between them.
The acceleration of the object if the net force is decreased = 0.13 m/s²
<h3>Further explanation</h3>
Given
A net force of 0.8 N acting on a 1.5-kg mass.
The net force is decreased to 0.2 N
Required
The acceleration of the object if the net force is decreased
Solution
Newton's 2nd law :
![\tt \sum F=m.a](https://tex.z-dn.net/?f=%5Ctt%20%5Csum%20F%3Dm.a)
The mass used in state 1 and 2 remains the same, at 1.5 kg
ΣF=0.8 N
m=1.5 kg
The acceleration, a:
![\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2](https://tex.z-dn.net/?f=%5Ctt%20a%3D%5Cdfrac%7B%5Csum%20F%7D%7Bm%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B0.8%7D%7B1.5%7D%5C%5C%5C%5Ca%3D0.53%60m%2Fs%5E2)
ΣF=0.2 N
m=1.5 kg
The acceleration, a:
![\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2](https://tex.z-dn.net/?f=%5Ctt%20a%3D%5Cdfrac%7B%5Csum%20F%7D%7Bm%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B0.2%7D%7B1.5%7D%5C%5C%5C%5Ca%3D0.13~m%2Fs%5E2)