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Annette [7]
3 years ago
7

Which of the following woud be expected to have the greatest impact on primary productivity?

Physics
1 answer:
leonid [27]3 years ago
3 0

Answer: C solar energy

Solar energy has the greatest  impact on primary productivity.

Explanation:

Primary productivity  is the amount of organic compounds synthesized from carbon dioxide. Primary production occurs by the process of photosynthesis. Since the process of photosynthesis uses sunlight as the energy source solar energy has the greatest impact on primary productivity.

The synthesis can occur in atmosphere as well as aquatic environment. The organisms that perform the function of primary production are called producers .In terrestrial regions plants are the producers and in aquatic systems algae are the  primary producers.

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3. When driving a car, the chemical energy in gasoline is converted to heat (thermal energy) in the engine. Most of this thermal
tekilochka [14]

Explanation:

As we know that the maximum of thermal energy will be converted into mechanical energy.( The thermal energy will be given to us by engine.)

But the total thermal energy will not be converted into the mechanical energy,  there will be some lost of energy. The lost of mechanical energy will be in multiple forms. 2 of them are

1.Heat : The mechanical energy heats up the engine and then it will lost some energy.

2.Noise : Some energy also lost in the sound or the noise comes out from the engine. It will consume some energy.

Also, the engine never be 100% efficient some amount of energy lost in environment also.

6 0
3 years ago
The formula v = √ 2.3 r models the maximum safe speed, v , in miles per hour, at which a car can travel on a curved road with ra
Archy [21]

Answer:

562 miles per hour.

Explanation:

As given in the question, the formula for the maximum speed on a curved road is

v=\sqrt{2.3} r

Given value of r=370 feet

So the maximum safe speed will be

v=\sqrt{2.3} \times 370 = 1.52\times 370 = 562.4 miles per hour.

Rounding off to the nearest whole number we get the maximum safe speed at the curved road is 562 miles per hour.

6 0
3 years ago
Humberto builds two circuits using identical components.Circuit 1: A series circuit with three lightbulbs Circuit 2: A parallel
PolarNik [594]
<span>Humberto builds two circuits using identical components,
and then adds components to each circuit.

Circuit 1:
A series circuit with three lightbulbs. 
Then add three more lightbulbs in series.

Circuit 2:
A parallel circuit with three lightbulbs
Then add two more lightbulbs on new branches
in parallel with each original bulb.

After adding the new lightbulbs in Circuit 1:
-- the voltage across each of the original bulbs is less,
-- the current through the whole series circuit is less,
-- the original three bulbs shine dimmer than before, and
-- the total power delivered from the battery is less.
-- The battery lasts longer.

After adding the new lightbulbs in Circuit 2:  
</span>-- the voltage across each of the original bulbs is doesn't change, 
-- the current through each original bulb doesn't change,
-- the original three bulbs shine just as bright as before, 
-- the total currrent drawn by the circuit, and the total current
delivered by the battery, increases, and
-- the total power delivered from the battery increases.
-- The battery runs down sooner.
5 0
3 years ago
Read 2 more answers
Physics question 28 plz help me
Alexus [3.1K]

Answer:

a. I = 30 A

b. E = 1080000 J = 1080 KJ

c. ΔT = 12.86°C

d. Cost = $ 4.32  

Explanation:

a.

The current in the coil is given by Ohm's Law:

V = IR\\I = \frac{V}{R}

where,

I = current = ?

V = Voltage = 120 V

R = Resistance = 4 Ω

Therefore,

I = \frac{120\ V}{4 \Omega}\\

<u>I = 30 A</u>

<u></u>

b.

The energy can be calculated as:

E = VIt\\E = (120\ V)(30\ A)(5\ min)(\frac{60\ s}{1\ min})\\

<u>E = 1080000 J = 1080 KJ</u>

<u></u>

c.

For the increase in the temperature of water:

E = mC\Delta T\\

where,

m = mass of water = 20 kg

C = specific heat of water = 4.2 KJ/kg.°C

Therefore,

1080\ KJ = (20\ kg)(4.2\ KJ/kg.^oC)\Delta T

<u>ΔT = 12.86°C</u>

<u></u>

d.

First, we will calculate the total energy consumed:

E=(Power)(Time)\\E=VI(Time)\\E = (120\ V)(30\ A)(0.5\ h/d)(30\ d)\\E = 54000\ Wh\\E = 54 KWh

Now, for the cost:

Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(54\ KWh)

<u>Cost = $ 4.32</u>

7 0
3 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
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