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Mademuasel [1]
3 years ago
10

Laney et al. (false memory):(a) Outline the rating scale used in the Food History Inventory [2 marks]

Physics
1 answer:
djverab [1.8K]3 years ago
6 0

Answer: The rating scale that is used in food history inventory is from 1 to 8.

Explanation:

In this case the participants have to rate 24 items on a scale of 1 to 8.There are variety of questions related to food or fooding habits.

The questions like do you go out for food?

Do you like bread ? if yes how will you rate it on a scale of 1 to 8.

The questions like this has to be answered in a way . It is done in order to see the preferences and false memory  regarding the food preference that people have.

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2. A multipurpose wiring tool can be used to
Alex_Xolod [135]

Answer:

Option C

Crimp terminals

Explanation:

It's possible to crimp terminals using a multipurpose wiring tool. Since the tool  selected for use during crimping also depends on the volume of work, the multipurpose wiring tool is recommended for use when the volume is small to medium. Basically, crimping tools are sized according to the wire gauge that they can fit. Since multipurpose has different sizes, that's why it's used for crimping tools.

5 0
3 years ago
What Is The frequency of an X Ray That had A Wavelength of 1.5* 10^-9
musickatia [10]
Here I come and we wanna go home!!!
7 0
3 years ago
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and the volume V satisfy th
jarptica [38.1K]

Answer: The volume is decreasing at a rate of 80 cm3/min

Explanation: Please see the attachments below

8 0
3 years ago
A test charge of -3x10^-7 C is located 7 cm to the right of a charge of -9x10^-6 C and 20 cm to the left of a charge of +10x10^-
musickatia [10]

Answer:

5.634 N rightwards

Explanation:

qo = - 3 x 10^-7 C

q1 = - 9 x 10^-6 C

q2 = 10 x 10^-6 C

r1 = 7 cm = 0.07 m

r2 = 20 cm = 0.2 m

The force on test charge due to q1 is F1 which is acting towards right

According to the Coulomb's law

F_{1}=\frac{Kq_{1}q_{0}}{r_{1}^{2}}

F1 = (9 x 10^9 x 9 x 10^-6 x 3 x 10^-7) / (0.07 x 0.07)

F1 = 4.959 N rightwards

The force on test charge due to q2 is F1 which is acting towards right

According to the Coulomb's law

F_{2}=\frac{Kq_{2}q_{0}}{r_{2}^{2}}

F2 = (9 x 10^9 x 10 x 10^-6 x 3 x 10^-7) / (0.2 x 0.2)

F2 = 0.675 N rightwards

Net force on the test charge

F = F1 + F2 = 4.959 + 0.675 = 5.634 N rightwards

3 0
3 years ago
A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr
balu736 [363]

Answer:

The x component of the electric field at y=2m is E_{x}=17.97\frac{N}{C}

Explanation:

For a linear charge, using <u>Gauss Law</u>, we get that the <em>Electric field (radial) has the following form</em>

E=\frac{\lambda}{2\pi\epsilon_{0}r}

<em>where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data</em>. So

E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

4 0
3 years ago
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