the force shown in figure 7-15 moves an object from x=0 to x=0.75 m. How much work is done by the force?

A 20 ohm lamp and a 5 ohm lamp are connected in series and placed across a potential difference of 50 V.

iogann1982 [59]

Hi there!

1.

Since the two resistors are in series, we can simply add:
$R_T = R_1 + R_2 + ... R_n$

$R_T = 20 + 5 = \boxed{25 \Omega}$

2.

In series, the potential difference of each resistor (lamp) ADDS UP. We can begin by finding the current through the circuit using Ohm's law:
$V = IR\\\\I = \frac{V}{R_T}$

Plug in the values:
$I = \frac{50}{25} = 2 A$

Now,

we can use Ohm's law to find the individual voltage for each lamp.

20 Ohm lamp:
$V = 2 * 20 = \boxed{40 V}$

5 Ohm lamp:
$V = 2 * 5 = \boxed{10 V}$

3.

To solve, we can use the power equation.

$P (\text{Watts})= IV$

Plug in the values for each.

20 Ohm lamp:
$P = 2 * 40 = \boxed{80 W}$

5 Ohm lamp:
$P = 2 * 10 = \boxed{100 W}$

7 0

1 year ago

The slotted arm OA rotates about a fixed axis through O. At the instant under consideration, θ = 36°, θ˙ = 36 deg/s, and θ¨ = 26

xz_007 [3.2K]

Answer:

F = 0.0545 N

Explanation:

Let's use Newton's second law for rotational movement

τ = I α

The moment of inertia for a bar supported by some ends is

I = 1/3 m L²

Torque is

τ = F L

Let's replace

F L = 1/3 m L² α

F = 1/3 m L α

Let's reduce angular acceleration to SI units

Alf = 26º / s² (π rad / 180º) = 0.454 rad / s²

Let's calculate

F = 1/3 0.5 0.72 0.454

F = 0.0545 N

4 0

3 years ago

An apple in a tree has a gravitational store of 8J. As it falls, it accelerates constantly until it hits the ground. What is the

natita [175]

Answer:

Explanation:

Given that on the tree the gravitational energy stored is 8J

Then, mgh = 8J.

The apple begins to fall and hit the ground, what is the maximum kinetic energy?

Using conservation of energy, as the above is about to hit the ground, the apple is at is maximum speed, and the height then is 0m, so the potential energy at the ground is zero, so all the potential of the apple at the too of the tree is converted to kinetic energy as it is about to hits the ground. Along the way to the ground, both the Kinetic energy and potential energy is conserved, it is notice that at the top of the tree, the apple has only potential energy since velocity is zero at top, and at the bottom of the tree the apple has only kinetic energy since potential energy is zero(height=0)

So,

K.E(max) = 8J

5 0

3 years ago

High-speed stroboscopic photographs show that the head of a 180 g golf club is traveling at 47 m/s just before it strikes a 46 g

inn [45]

Answer:

47 m/s

Explanation:

golf club mass, mc = 180 g

golf ball mass, mb = 46 g

initial golf club speed, vc1 = 47 m/s

final golf club speed, vc2 = 35 m/s

initial golf ball speed, vb1 = 0 m/s

final golf ball speed, vb2 = ? m/s

The total momentum is conserved, then:

mc*vc1 + mb*vb1 = mc*vc2 + mb*vb2

Replacing with data and solving (dimension are omitted):

180*47 + 46*0 = 180*35 + 46*vb2

vb2 = (180*47 - 180*35)/46

vb2 = 47 m/s

7 0

3 years ago

Read 2 more answers

I would give brainliest if you have me!

Ket [755]

She can first measure the mass on the scale, then measure the cm^3 by putting water in the cylinder and measuring the original water level minus the water level after you put the rock in. The take the measurement from the scale (g) and divide it by the measurement in the graduated cylinder (c^3).

5 0

3 years ago