4 years ago

the force shown in figure 7-15 moves an object from x=0 to x=0.75 m. How much work is done by the force?

Physics

1 answer:

Phantasy [73]4 years ago

6 0

Work is force multiplied by the distance the force moves the object

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Two spherical objects are separated by a distance that is 9.00 X 10m The objects are initially electrically neutral and are very

romanna [79]

Answer: 3.2 * 10^-3 C

Explanation: In order to solve this problem we have to use the Coulomb force given by:

F=k*q^2/ d^2 where he consider the same charge for each point

so, we have

q^2= F*d^2/k= 1.137* (10 C*9*10m)^2/9*10^9 N*m^2/C^2)=3.2 * 10^-3 C.

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3 years ago

The equivalent resistance of a complex circuit is usually determined by a dividing the sum of the individual resistances by the

katen-ka-za [31]

Answer:

Explanation:

we simplify the circuit into groups to obtain a complete circuit I.e series and parallel circuit

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3 years ago

An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acce

ankoles [38]

Answer:

d=510.2m

t=10.2s

Explanation:

The formulas for accelerated motion are:

$v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}$

From them we can get $v^2=v_0^2+2ad$ .

We have:

$v-v_0=at\\t=\frac{v-v_0}{a}$

And substitute:

$x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}$

We multiply both sides by 2a, and continue:

$2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2$

Being d the displacement $x-x_0$ , we have $v^2=v_0^2+2ad$

For our exercise, we will write this as:

$d=\frac{v^2-v_0^2}{2a}$

And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:

$d=\frac{-v_0^2}{2a}=\frac{-(100m/s)^2}{2(-9,8m/s^2)}=510.2m$

For the time we use:

$t=\frac{v-v_0}{a}=\frac{-v_0}{a}=\frac{-(100m/s)}{(-9.8m/s^2)}=10.2s$

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4 years ago

the coefficient of static friction between a 40 kg picnic table and the ground below is .43. what is the greatest horizontal for

Gre4nikov [31]

The force equals the coefficient of static friction times the weight. Use gravity g=9.8 m/s^2
0.43*40*9.8=16.856 N

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4 years ago

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Vera_Pavlovna [14]

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