Question

A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coefficient of friction of the skis on snow is 0.05, then what is the weight of the skier?

Answer 1

Answer:

$1200\ \text{N}$

Explanation:

F = Force on the skier = 60 N

$\mu$ = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

$F=\mu w$

$\Rightarrow w=\dfrac{F}{\mu}$

$\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}$

$\Rightarrow w=1200\ \text{N}$

Weight of the skier on which the force is being applied is $1200\ \text{N}$ .