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Anna11 [10]
3 years ago
11

A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coeffici

ent of friction of the skis on snow is 0.05, then what is the weight of the skier?
Physics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

1200\ \text{N}

Explanation:

F = Force on the skier = 60 N

\mu = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

F=\mu w

\Rightarrow w=\dfrac{F}{\mu}

\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}

\Rightarrow w=1200\ \text{N}

Weight of the skier on which the force is being applied is 1200\ \text{N} .

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The time interval for which the proton remains in the field is -

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According to the question, we have -

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Now -

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Δt = $\frac{\pi R}{40}

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