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lidiya [134]
4 years ago
9

Josh manages security at a power plant. The facility is sensitive, and security is very important. He would like to incorporate

two-factor authentications with physical security. Which of the options below is the best way to meet this requirement?
Physics
1 answer:
Studentka2010 [4]4 years ago
8 0
  • Question: Josh manages security at a power plant. The facility is sensitive, and security is very important. He would like to incorporate two-factor authentications with physical security. Which of the options below is the best way to meet this requirement?  A) Smart cards B) A mantrap with a smart card at one door and a pin keypad at the other door C) A mantrap with video surveillance D) A fence with smart card gate access  Answer: The correct answer is (B) A mantrap with a smart card at one door and a pin keypad at the other door  Explanation: Multi-factor access control systems are access control systems that authorises access only after more than one piece of evidence is presented to authenticate a user. The mechanisms used in multi-factor authentication include 1.  Knowledge (something the user and only the user knows),  2.  Possession (something the user and only the user has), and  3.  Inherence (something the user and only the user is). A two-factor authentication system uses two of these mechanisms to grant or deny access. An authentication system that uses a mantrap with a smart card (possession) on one door and a pin keypad (knowledge ) on the other door is a two factor authentication system.
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A shopper pushes a 5.32 kg grocery cart
Juli2301 [7.4K]

Answer:

\text { acceleration of the cart is } 10.94 \mathrm{m} / \mathrm{s}^{2}

Explanation:

According to “Newton's second law”

“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

Force = mass × acceleration

\text { Acceleration }=\frac{\text { force }}{\text { mass }}

Given that,

Mass = 5.32 kg

\text { Force }=12.7 \mathrm{N} \text { forces at }-28.7^{\circ}

x=-28.7^{\circ}

F = 12.7N

Normal force = mg + F sinx,  

“m” being the object's "mass",  

“g” being the "acceleration of gravity",

“x” being the "angle of the cart"

\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}\text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^ 2 \text { on Earth })

To find normal force substitute the values in the formula,

Normal force = 5.32 × 9.8 + 12.7 × sin(-28.7)

Normal force = 52.136 + 12.7 × 0.480

Normal force = 52.136 + 6.096

Normal force = 58.232 N

<u>Acceleration of the cart</u>:

\text { Acceleration }=\frac{\text {Normal force}}{\text { mass }}

\text { Acceleration }=\frac{58.232}{5.32}

\text { Acceleration }=10.94 \mathrm{m} / \mathrm{s}^{2}

\text { Therefore, "acceleration of the cart" is } 10.94 \mathrm{m} / \mathrm{s}^{2}

7 0
3 years ago
Read 2 more answers
A whistle you use to call your hunting dog has a frequency of 21 kHz, but your dog is ignoring it. You suspect the whistle may n
uranmaximum [27]

The Doppler effect is the right concept to solve this problem. The Doppler effect is understood as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be described as,

f = (1-\frac{v_0}{v})f_0

Here,

f_0 = Frequency of the sound from the Whistle

f = Frequency of sound heard

v = Speed of the sound in the Air

Replacing we have that

1- \frac{v_0}{343} = \frac{20kHz}{21kHz}

\frac{v_0}{343} = 1-\frac{20}{21}

\frac{v_0}{343} = \frac{1}{21}

v_0 = \frac{1}{21}(343)

v_0 = 16.33m/s

Therefore the minimum speed to know if the whistle is working is 16.33m/s

3 0
4 years ago
Marisol drives north at 64.3 km/h. How far does Marisol travel after 5.8 h?
Nady [450]

Answer:

372.94 km

d= st

= (64.3 km/h)(5.8h)

=372.94 km

3 0
3 years ago
Read 2 more answers
The power supply for your answering machine is a small black cube that plugs directly into an electric outlet. The main componen
svet-max [94.6K]

If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.

Answer: Option B

<u>Explanation:</u>

A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.

Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.

4 0
3 years ago
Just think about this.
diamong [38]
This ain’t the place, bud. If you have a QUESTION, then you can post it here.
8 0
3 years ago
Read 2 more answers
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