Accuracy is a general concept while precision is more of a mathematical concept.
Answer:
λ = 28,14 m
Explanation:
To find the wavelength of the wave you use the following formula:
(1)
v: speed of the wave = 1,97 m/s
λ: wavelength
f: frequency of the wave = 0,07 Hz
You replace the values of v and f in the equation (1) and solve for λ:
hence, the wavelength of the wave is 28,14 m
Answer:
MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...
Explanation:
TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....
TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..
MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g
Range =Search Results
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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin 2 θ i g .
Answer:
x = 0.9 m
Explanation:
For this exercise we must use the rotational equilibrium relation, we will assume that the counterclockwise rotations are positive
∑ τ = 0
60 1.5 - 78 1.5 + 30 x = 0
where x is measured from the left side of the fulcrum
90 - 117 + 30 x = 0
x = 27/30
x = 0.9 m
In summary the center of mass is on the side of the lightest weight x = 0.9 m
