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3 years ago

PLEASE HELP! PRE LAB FOR AP CHEM

Chemistry

1 answer:

saw5 [17]3 years ago

7 0

Answer:

Balanced net ionic equation;

2MnO₄⁻ + 16H⁺ + 5C₂O₄²⁻ → 2Mn²⁺ + 8H₂O + 10 CO₂

Explanation:

This is an example of a redox titration where acidified potassium permanganate (KMnO₄) is titrated against oxalic acid (H₂C₂O₄).
A redox reaction is a type of reaction that involves both reduction and oxidation.
One reactant of the reaction gains electrons(reduction) while another loses electrons(oxidation).
During the redox reaction, H⁺/KMnO₄ undergoes reduction while the oxalic acid undergoes oxidation.
Therefore, KMnO₄ is the oxidizing agent while H₂C₂O₄ is the reducing agent.
The net ionic reaction will be;

2MnO₄⁻ + 16H⁺ + 5C₂O₄²⁻ → 2Mn²⁺ + 8H₂O + 10 CO₂

From the reaction, MnO₄⁻ is reduced to 2Mn²⁺ while C₂O₄²⁻ is oxidized to CO₂.
Therefore, two moles of KMnO₄ will react with 5 moles of oxalic acid.

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What is the law of multiple proportions?

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Answer:

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3 years ago

How many cm 3 are in 0.014 in 3? (1 in = 2.54 cm)

pashok25 [27]

Answer:

0.229 cm³.

Explanation:

The following data were obtained from the question:

Volume (in in³) = 0.014 in³

Volume (in cm³) =?

1 in = 2.54 cm

Next, we shall determine a conversion scale to convert from in³ to cm³. This can be obtained as follow:

1 in = 2.54 cm

Therefore,

1 in³ = 2.54³ cm³

1 in³ = 16.387 cm³

Finally, we shall convert 0.014 in³ to cm³. This can be obtained as follow:

1 in³ = 16.387 cm³

Therefore,

0.014 in³ = 0.014 in³ × 16.387 cm³ / 1 in³

0.014 in³ = 0.229 cm³

Thus, 0.014 in³ is equivalent to 0.229 cm³.

7 0

3 years ago

HELP ME PLEASE Im stuck I said d but please make sure

morpeh [17]

Answer:

The fourth one.

Explanation:

The fourth graph shows an object speeding up ( accelerating ) coz the velocity (tangent at the curve ) at every point is different, hence denoting an acceleration.

3 0

3 years ago

At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.600 M. N2(g)+O2(g)↽−−⇀2NO(g) If

cestrela7 [59]

Answer:

0.84M

Explanation:

Hello,

At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:

$K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9$

Now, the new equilibrium condition, taking into account the change x, becomes:

$9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}$

Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:

$\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}$