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2 years ago

If you observe the a full moon on January 12th on what date would you observe the next new moon

Chemistry

1 answer:

crimeas [40]2 years ago

5 0

Answer:

February 12th, the reason being, studies have shown a full moon happens about every 29.5 days, so round it up to 30, which would be a month later than January 12th! A month later from January 12th would be February 12th!

Explanation:

Hope this helps God bless!

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he balanced net ionic equation for precipitation of CaCO 3 when aqueous solutions of Na 2CO 3 and CaCl 2 are mixed is ________.

ale4655 [162]

Answer:

Net ionic equation: $Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)$

Explanation:

Reaction between $Na_{2}CO_{3}$ and $CaCl_{2}$ is an example of double decomposition reaction where each cations and anions of each salt exchange their partners during reaction to form $CaCO_{3}$ and NaCl

$CaCO_{3}$ is an insoluble salt. Hence precipitation of $CaCO_{3}$ has been observed.

Molecular equation: $Na_{2}CO_{3}(aq.)+CaCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CaCO_{3}(s)$

Total ionic equation:

$2Na^{+}(aq.)+CO_{3}^{2-}(aq.)+Ca^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow CaCO_{3}(s)+2Na^{+}(aq.)+2Cl^{-}(aq.)$

Here $Na^{+}$ and $Na^{+}$ are spectator ions. Therefore they are eliminated from both side of total ionic equation to get net ionic equation.

Net ionic equation: $Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)$

6 0

3 years ago

Answer truthfully:))

BartSMP [9]

Answer:

b) velocity.

c) velocity, m/s²

d)change in velocity, change in direction, change in both velocity and direction.

e) increasing or decreasing

3 0

2 years ago

Why air is classified as a mixture

Vika [28.1K]

Answer:

See explanation

Explanation:

Air contains a mixture of several molecules and compounds such as oxygen and carbon dioxide.

5 0

2 years ago

Which of the following is equal to 1 mole?

nadya68 [22]

They are all equal to one mole (all of the above).

7 0

3 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)$

The expression for $K_c$ is written as:

$K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}$

$K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}$

$K_c=3.72$

Thus the value of the equilibrium constant Kc for this reaction is 3.72

5 0

2 years ago