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valina [46]
3 years ago
13

Which of the following are products of the light-dependent reactions of photosynthesis that are utilized in the light-independen

t reactions?
ATP and NADPH
water and oxygen
oxygen and glucose
carbon dioxide and glucose
Chemistry
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

\boxed {\tt Oxygen \ and \ glucose}

Explanation:

The photosynthesis equation is:

energy+6CO₂+6H₂O--> C₆H₁₂O₆+6O₂

The reactants are light energy, carbon dioxide, and water. The products are <u>glucose and oxygen.</u>

<u />

The products of photosynthesis become the products of the light-independent reaction called cellular respiration, which creates useable energy. Therefore, the correct answer is oxygen and glucose.

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If you know the mass of an object you can calculate its weight with the formula
Vikki [24]
Answer: True

The formula of weight is w = mg, where m is the mass and g is the acceleration of gravity. If you want to calculate an object's weight, you need to know the two components: mass and gravity. 

You only need to know the mass of the object because the acceleration of gravity is ALWAYS (assuming the object is on Earth) 9.8 m/s^2. 
3 0
3 years ago
Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.
Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O

Number of atoms present on reactant side are as follows.

  • C = 1
  • H = 4
  • O = 2

Number of atoms present on product side are as follows.

  • C = 1
  • H = 2
  • O = 3

To balance this equation, multiply O_{2} by 2 on reactant side. Also, multiply H_{2}O by 2 on product side. Hence, the equation can be rewritten as follows.

CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O

Now, the number of atoms present on reactant side are as follows.

  • C = 1
  • H = 4
  • O = 4

Number of atoms present on product side are as follows.

  • C = 1
  • H = 4
  • O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

4 0
3 years ago
An example of a solution that is formed endothermically is the one used in
Makovka662 [10]

Cold Packs

<u>Explanation:</u>

Endothermic reactions are reactions in which heat is absorbed from the surroundings and the container in which the reaction takes place is said to be very cold. In cold packs, ammonium nitrate is used, is dissolved in solution is said to be an example of endothermic reaction, in this the heat energy is absorbed from the surroundings. In this the solute increases the solubility with the rise in temperature, and also used in cold packs.

3 0
3 years ago
Cereal is an example of what type of matter?
Elena L [17]
A heterogeneous mixture since you can separate the ingredients that make it up.
5 0
3 years ago
Read 2 more answers
4Fe (s) + 3 O2 (g) → 2 Fe2O3 (s)
Novay_Z [31]

Explanation:

The number acquired by an element after the lose or gain of an electron is called oxidation number.

For example, 4Fe(s) + 3O_{2}(g) \rightarrow 2Fe_{2}O_{3}(s)

Here, oxidation number of Fe(s) is 0 and Fe in Fe_{2}O_{3} is +3.

Oxidation number of O in O_{2}(g) is 0 as it is present in its elemental state.

The oxidation number of O in Fe_{2}O_{3} is calculated as follows.

2(3) + 3x = 0\\6 + 3x = 0\\x = \frac{-6}{3}\\= -2

Hence,  oxidation number of O in Fe_{2}O_{3} is -2.

  • The loss of electrons by an element or substance is called oxidation. Here, electrons are being lost by Fe(s) as an increase in oxidation state is occurring. So, Fe(s) is oxidized.
  • The gain of electrons by an element or substance is called reduction. Here, electrons are being added to O_{2} as a decrease in its oxidation state is occurring. So, O_{2}  is reduced.
  • An element or compound which is being reduced is called oxidizing agent. Here, O_{2}  is the oxidizing agent.
  • An element or compound which is being oxidized is called reducing agent. Here, Fe(s) is the reducing agent.
5 0
3 years ago
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