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-BARSIC- [3]
3 years ago
6

HELP I AM IN AN EXAM AND I NEED HELP PLEASE I WILL MAKE BRAINLIEST!!!The picture shows two different species of mammals that use

wings to glide among tree tops. However, scientists theorize that these mammals are not closely related.
Which best explains why these two animals look so similar if they are not closely related?

They have analogous structures that developed for different functions.
They have homologous structures that developed for different functions.
They live in similar environments and have analogous structures adapted to them.
They live in similar environments and have homologous structures adapted to them.
Chemistry
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:They live in similar environments and have analogous structures adapted to them.

Explanation: Analogous mean comparable in certain respects, typically in a way which makes clearer the nature of the things compared. So if they are not releatd then they are connected to there shared environment.

Natalka [10]3 years ago
8 0

Answer:

They live in similar environments and have analogous structures adapted to them.

Explanation: TOOK THE TEST

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Read 2 more answers
Limiting Reactants—————-
denis-greek [22]

Answer:

21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

  • Mg: 24.301;
  • O: 15.999.

How many moles of MgO will be produced if Mg is the limiting reactant?

Number of moles of Mg:

\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

7 0
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