The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
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According to the task, you are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C
<span>The you go :
</span>
n1 n2 0
-x -x +2x
After that you have to use the formula
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>
I am absolutely sure that this would be helpful for you.
Answer:
hope this help by the way found off of yahoo
Explanation:
Calculate the number of grams of nitrogen dioxide that are produced from
4 moles of nitric oxide.
2NO(g) + O2(g) -->2NO2(g)
I really need help with this... I need to know how to work it too... I can balance it out but not sure about grams... This is it balanced out with 4 moles of nitric oxide
4NO(g) + 2O2(g) ->4NO2(g) please help and explain i want to learn this
Answer:
1 cubic mile = 1.101 * 10^12 US gallons
1 US bbl oil = 42 US gallons = 3.8143*10^ -11 cubic miles
Explanation:
The number of the exponent of the oil reserve is not very well shown in the question so, I provide you the conversion of bbl oil into cubic mile, the only thing you have to do is multiply the number of bbls of the reserve for the conversion in cubic miles and you'll have the answer.
