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andriy [413]
3 years ago
5

What is the pOH of a solution of HNO3 that has [OH-] = 9.50 10-9 M?

Chemistry
2 answers:
bekas [8.4K]3 years ago
6 0

Answer:

The pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

Explanation:

Given data:

[OH⁻] = 9.50 ×10⁻⁹M

pOH = ?

Solution:

pOH = -log[OH⁻]

Now we will put the value of OH⁻ concentration.

pOH = -log[9.50 ×10⁻⁹M]

pOH = 8

Thus the pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

Over [174]3 years ago
5 0

Answer:

the answer is 8.02

Explanation:

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2 years ago
Write the name of the alkyne next to the drawing of the molecule. (2 points)
azamat

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

<h3>What is alkyne?</h3>

Molecules that contain a triple bond between two carbon atoms are known as alkynes.

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

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Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

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The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

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brainly.com/question/23508203

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6 0
2 years ago
CH3 + HCl &lt;=&gt; CH3Cl + H2O
dmitriy555 [2]

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

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