1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhuklara [117]
3 years ago
13

ured length.  Measurement errors are another type of uncertainty involved in single measurements. Suppose we measure the diamet

er of a disk. The minimum length that can be measured on the stick is 1 mm (0.1 cm). If the diameter lies somewhere between 5.1 cm and 5.2 cm, which value do we report? In such cases the value is reported as 5.15 ± 0.05 cm. Note that the uncertainty of the measurement is one half the smallest tick mark on the measuring device. This applies to all instruments. A sound experimental procedure involves several measurements of the physical quantities required in one of several ways. Once those measurements have been made, we compute the statistical quantities listed in the key concepts above to make inferences from the data obtained. Question 1 (write down answers on Report Sheets) Below are three sets of measurements of the boiling point of water at 1 standard atmosphere (atm): Measurement 1 2 3 4 5 Set A 99.8 °C 99.8 °C 99.8 °C 99.8 °C 99.8 °C Set B 100.0
Physics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

  T = (99.78 ±0.05) ºC

Explanation:

This problem refers to the procedure to perform the measurements and their correct reporting.

Suppose that the thermometer used has an appreciation of 0.1ºC and the values ​​of 5 measurements resulted in

 #     T (ºC)

 1      99.8

 2     99.7

 3     99.7

 4     99.8

 5     99.9

the processing calculate mean value

   T_average = ∑ T_{i} / n

   T_average = (99.8 + 99.7 + 99.7 + 99.8 + 99.9) / 5

   T_average = 99.78ºC

the absolute error or uncertainty of the measurement is half the appreciation of the instrument

       ΔT = ± 0.05ºC

so the result must be written

        T = (99.78 ±0.05) ºC

You might be interested in
A car of mass m accelerates from speed v_1 to speed v_2 while going up a slope that makes an angle theta with the horizontal. Th
Karo-lina-s [1.5K]

Answer:

Work done by external force is given as

Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

Explanation:

As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car

so we will have

Work_{external} + Work_{gravity} + Work_{friction} = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

now we have

W_{gravity} = -mg(Lsin\theta)

W_{friction} = -\mu mgcos(\theta) L

so from above equation

Work_{external} - mgLsin\theta - \mu mgLcos(\theta) = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

so from above equation work done by external force is given as

Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

8 0
3 years ago
0.A 20-g bullet moving at 1 000 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. What is the kinetic
Fiesta28 [93]

Answer:

KE = 0.162 KJ

Explanation:

given,

mass of bullet (m)= 20 g = 0.02 Kg

speed of the bullet (u)= 1000 m/s

mass of block(M) = 1 Kg

velocity of bullet after collision (v)= 100 m/s

kinetic energy = ?

using conservation of momentum

m u = m v + M V

0.02 x 1000 = 0.02 x 100 + 1 x V

20 = 2 + V

V = 18 m/s

now,

Kinetic energy of the block

KE = \dfrac{1}{2}mv^2

KE = \dfrac{1}{2}\times 1 \times 18^2

KE = 162 J

KE = 0.162 KJ

4 0
3 years ago
a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of
Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               F_t -W = m a

Whera F_t is the trampoline force

Body weight is

                W = mg

We substitute

              F_t - mg = ma

              a =\frac{F_t - m g}{m}

Let's calculate

              a = \frac{375 - 75 \ 9.8 }{75}

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
The pressure, p, of water (in pounds per square foot) at a depth of d feet below the surface is given by the formula p=15+15/33d
Viefleur [7K]
The pressure of the water on the diver is given in an expression written as:

<span>p=15+15/33d

where p is the pressure and d is the distance of the diver </span><span>below the surface.

The pressure is calculated as follows:

</span>p=15+15/33(100) = 15.00  pounds per square feet

Therefore, the correct answer is option A.
8 0
3 years ago
Read 2 more answers
Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of
Oliga [24]

Answer:

8.4168\times 10^{-21}\ kgm/s upward

4.725 kgm/s to the right

468.6 kgm/s southwest

1.782\times 10^{49}\ kgm/s forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s

The momentum of the proton is 8.4168\times 10^{-21}\ kgm/s upward

Bullet

p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s

The momentum of the sprinter is 1.782\times 10^{29}\ kgm/s forward

4 0
3 years ago
Other questions:
  • A sea breeze occurs because warm air rises on land and moves toward the ocean to cool. The cool air then moves from the ocean to
    13·2 answers
  • In deep space there is very little friction once they are launched into a probe into deep space where there are no external forc
    8·2 answers
  • What happens when someone is walking across the carpeted room then touches a metal door knob
    11·1 answer
  • When a ball is thrown up vertically, explain what happens and explain why final velocity is zero ​
    10·1 answer
  • If our frame of reference was the sun would the earth be moving?
    6·1 answer
  • A 79 kg person sits on a 3.7 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.3 cm in diameter
    8·1 answer
  • A massive object can distort the light of more distant objects behind it through the phenomenon that we call __________
    7·1 answer
  • It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
    7·1 answer
  • Whichiscorrect?(A)anopaqueobjectdoesnotallowlighttopassthroughit.(B)an
    7·2 answers
  • The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, w
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!