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zhuklara [117]
3 years ago
13

ured length.  Measurement errors are another type of uncertainty involved in single measurements. Suppose we measure the diamet

er of a disk. The minimum length that can be measured on the stick is 1 mm (0.1 cm). If the diameter lies somewhere between 5.1 cm and 5.2 cm, which value do we report? In such cases the value is reported as 5.15 ± 0.05 cm. Note that the uncertainty of the measurement is one half the smallest tick mark on the measuring device. This applies to all instruments. A sound experimental procedure involves several measurements of the physical quantities required in one of several ways. Once those measurements have been made, we compute the statistical quantities listed in the key concepts above to make inferences from the data obtained. Question 1 (write down answers on Report Sheets) Below are three sets of measurements of the boiling point of water at 1 standard atmosphere (atm): Measurement 1 2 3 4 5 Set A 99.8 °C 99.8 °C 99.8 °C 99.8 °C 99.8 °C Set B 100.0
Physics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

  T = (99.78 ±0.05) ºC

Explanation:

This problem refers to the procedure to perform the measurements and their correct reporting.

Suppose that the thermometer used has an appreciation of 0.1ºC and the values ​​of 5 measurements resulted in

 #     T (ºC)

 1      99.8

 2     99.7

 3     99.7

 4     99.8

 5     99.9

the processing calculate mean value

   T_average = ∑ T_{i} / n

   T_average = (99.8 + 99.7 + 99.7 + 99.8 + 99.9) / 5

   T_average = 99.78ºC

the absolute error or uncertainty of the measurement is half the appreciation of the instrument

       ΔT = ± 0.05ºC

so the result must be written

        T = (99.78 ±0.05) ºC

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If for every action force an equal and opposite reaction force exists, how can anything ever be accelerated?
Anon25 [30]

The action and reaction forces act on different objects, therefore the net force is not always zero

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"</em>

From the statement above, it is clear that the action and the reaction forces act on different objects. In fact, the action force acts on object B, while the reaction force acts on object A. This means that the two forces never appear in the same free-body diagram of the same object, and therefore when computing the net force acting on an object, we take into account only one of the two forces, never both.

For instance, imagine you are pushing a box along the floor with a force F (action). The box is exerting back on you a reaction force of equal magnitude in the opposite direction, - F. However, if we want to compute the net force on the box, we just take into account the action (F), not the reaction, because the reaction is acting on you, not on the box.

Therefore, the correct answer is

The action and reaction forces act on different objects, therefore the net force is not always zero

Learn more about Newton's third law:

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3 0
3 years ago
A crate rests on the flatbed of a truck that is initially traveling at 15 m/s on a level road. The driver applies the brakes and
lina2011 [118]

Answer:0.3

Explanation:

Given

velocity of car=15 m/s

truck brought to halt in a distance of 38 m

We know

v^2-u^2=2as

Final velocity (v)=0

0-(15)^2=2(a)(38)

a=\frac{-225}{76}

a=-2.96 m/s^2  (deceleration)

Therefore minimum coefficient of friction \mu will be

\mu \times g=a

\mu =\frac{a}{g}

\mu =\frac{2.96}{9.8}=0.302

7 0
4 years ago
Safety warning: What three problems can happen when you connect a short wire between the positive and negative ends of a battery
STALIN [3.7K]

Answer:

if you're not safe then 1 cause is you can get very hurt and also you could be in very deep Danger and the last reason is you could also get killed

4 0
3 years ago
A record is spinning at the rate of 25rpm. If a ladybug is sitting 10cm from the center of the record.
marin [14]

A) Angular speed: 0.42 rev/s

B) Frequency: 0.42 Hz

C) Tangential speed: 26.4 cm/s

D) Distance travelled: 528 cm

Explanation:

A)

In this problem, the ladybug is rotating together with the record.

The angular velocity of the ladybug, which is defined as the rate of change of the angular position of the ladybug, in this problem is

\omega = 25 rpm

where here it is measured in revolutions per minute.

Keeping in mind that

1 minute = 60 seconds

We can rewrite the angular speed in revolutions per second:

\omega = 25 \frac{rev}{min} \cdot \frac{1}{60 s/min}=0.42 rev/s

B)

The relationship between angular speed and frequency of revolution for a rotational motion is given by the equation

\omega = 2 \pi f (1)

where

\omega is the angular speed

f is the frequency of revolution

For the ladybug in this problem,

\omega=0.42 rev/s

Keeping in mind that 1 rev = 2\pi rad, the angular speed can be rewritten as

\omega = 0.42 \frac{rev}{s} \cdot 2\pi = 2\pi \cdot 0.42

And re-arranginf eq.(1), we can find the frequency:

f=\frac{\omega}{2\pi}=\frac{(2\pi)0.42}{2\pi}=0.42 Hz

And the frequency is the number of complete revolutions made per second.

C)

For an object in circular motion, the tangential speed is related to the angular speed by the equation

v=\omega r

where

\omega is the angular speed

v is the tangential speed

r is the distance of the object from the axis of rotation

For the ladybug here,

\omega = 2\pi \cdot 0.42 rad/s is the angular speed

r = 10 cm = 0.10 m is the distance from the center of the record

So, its tangential speed is

v=(2\pi \cdot 0.42)(0.10)=0.264 m/s = 26.4 cm/s

D)

The tangential speed of the ladybug in this motion is constant (because the angular speed is also constant), so we can find the distance travelled using the equation for uniform motion:

d=vt

where

v is the tangential speed

t is the time elapsed

Here we have:

v = 26.4 cm/s (tangential speed)

t = 20 s

Therefoe, the distance covered by the ladybug is

d=(26.4)(20)=528 cm

Learn more about circular motion:

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brainly.com/question/2506028

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7 0
4 years ago
Read 2 more answers
A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 206
vampirchik [111]
Power = (voltage) x (current). The motor consumes (12)x(206)=2,472 watts. Some of it is dissipated as heat, but most of it is used to do useful work by turning the engine over to make it start.
5 0
3 years ago
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