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Ilya [14]
3 years ago
14

If for every action force an equal and opposite reaction force exists, how can anything ever be accelerated?

Physics
1 answer:
Anon25 [30]3 years ago
3 0

The action and reaction forces act on different objects, therefore the net force is not always zero

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"</em>

From the statement above, it is clear that the action and the reaction forces act on different objects. In fact, the action force acts on object B, while the reaction force acts on object A. This means that the two forces never appear in the same free-body diagram of the same object, and therefore when computing the net force acting on an object, we take into account only one of the two forces, never both.

For instance, imagine you are pushing a box along the floor with a force F (action). The box is exerting back on you a reaction force of equal magnitude in the opposite direction, - F. However, if we want to compute the net force on the box, we just take into account the action (F), not the reaction, because the reaction is acting on you, not on the box.

Therefore, the correct answer is

The action and reaction forces act on different objects, therefore the net force is not always zero

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

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3 years ago
A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre
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Answer:

The time taken is  t =  0.356 \ s

Explanation:

From the question we are told that

  The length of steel the wire is  l_1  = 31.0 \ m

   The  length of the  copper wire is  l_2  = 17.0 \ m

    The  diameter of the wire is  d =  1.00 \ m  =  1.0 *10^{-3} \ m

     The  tension is  T  =  122 \ N

     

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

              t  =  t_s  +  t_c

Where  t_s is the time taken to transverse the steel wire which is mathematically represented as

         t_s  = l_1 *  [ \sqrt{ \frac{\rho * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_s is the density of steel with a value  \rho_s  =  8920 \ kg/m^3

   So

      t_s  = 31 *  [ \sqrt{ \frac{8920 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_s  = 0.235 \ s

 And

        t_c is the time taken to transverse the copper wire which is mathematically represented as

      t_c  = l_2 *  [ \sqrt{ \frac{\rho_c * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_c is the density of steel with a value  \rho_s  =  7860 \ kg/m^3

 So

      t_c  = 17 *  [ \sqrt{ \frac{7860 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_c  =0.121

So  

   t  = t_c  + t_s

    t =  0.121 + 0.235

    t =  0.356 \ s

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