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Rainbow [258]
3 years ago
15

What is the area of a 20-gon with radius 5 in

Mathematics
1 answer:
Degger [83]3 years ago
8 0
Assuming that is the circumradius:
Polygon Area = [r^2 * n * sin (360 / n)] / 2
Polygon Area = (25 * 20 * sin (18)) / 2
Polygon Area = (500 * 0.30902) / 2
Polygon Area = <span> <span> <span> 77.255 </span> </span> </span>





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Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.​
Helga [31]
<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0
3 years ago
Plez halp with question bc im smol brain
Studentka2010 [4]

Answer:

B. y= 2x–15

Step-by-step explanation:

The equation that represents the line that passes through the points (8, 1) and (10,5) is y= 2x–15

"x" is found on the left hand side of the bracket and "y" is found on the right hand side of the bracket :)

(8, 1) and (10, 5)

x in the first bracket is 8 and x in the second bracket is 10.

y in the first bracket is 1 and y in the second bracket is 5.

When this equation is applied to find the value for y we get:

y= 2x-15

y= 2(8)-15

y= 16-15

y= 1

y= 2x-15

y= 2(10)-15

y= 20-15

y= 5

We got back the values of y and this means that the equation was correctly chosen and the answer is correct :)

6 0
3 years ago
The method of grd 5 of using multiplication<br>24<br>×35<br>=​
Mariana [72]

Answer:

24 x 35 = 840

Step-by-step explanation:

3 0
3 years ago
class A has 13 pupils and class b has 28 pupils both classes sit the same maths test the mean score for class A is 23 the mean s
Wittaler [7]

Answer:

46.22

Step-by-step explanation:

Class A total= 23 x 13= 299

Clas B total= 57 x 28= 1596

total score= 299 + 1596 = 1895

total mean= 1895 ÷ (13+28) = 1895 ÷ 41

                 = 46.22

7 0
2 years ago
Which statement is true?
Allushta [10]
Im pretty sure it is the first one
5 0
3 years ago
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