Answer:
the object is in the air on the time interval (0.24 sec, 6.51 sec)
Step-by-step explanation:
The object is 'in the air' for all t such that h> 0. We need to find the roots of h = -16t^2 + 108t - 25 = 0. From the graph we see that both t values are positive. Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.
Use the quadratic formula to find the roots of h(t). The coefficients of t are {-16, 108, -25}, and so the discriminant b^2 - 4ac is
108² - 4(-16)(-25) = 11664 - 1600 = 10064, whose square root is 100.32.
Then the quadratic formula x = (-b ± √[b² - 4ac)/(2a) becomes
-108 ± 100.32 108 ± 100.32
t = ---------------------- = --------------------- = 3.375 ± 3.135
2(-16) 32
or t = 6.51 or t = 0.24 (both times expressed in seconds).
So, again, the object is in the air on the time interval (0.24 sec, 6.51 sec)
Answer:
the picture is not clear of that number in diagram
Answ
This is false
Step-by-step explanation:
Answer:
fourteen and one-hundred-two
Step-by-step explanation:
we tend to read "." as "point" but the proper reading would be to read the number left to the decimal point (14), add the word "and" and then read the number to the right of the decimal point (102)
Answer:
first blank 39, second 9/39 i think, and third 351
Step-by-step explanation:
i haven't done something like this in a long time so i dont know if its completely correct or correct at all
