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omeli [17]
4 years ago
10

A marble rolls off a table with a speed of 2.30 m/s. If the table is 1.12 m high, how far from the

Physics
1 answer:
Vlada [557]4 years ago
6 0

Answer:

1.10 m

Explanation:

First, find the time it takes to land.

Given, in the y direction:

Δy = 1.12 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(1.12 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.478 s

Next, find the distance traveled in that time.

Given, in the x direction:

v₀ = 2.30 m/s

a = 0 m/s²

t = 0.478 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.30 m/s) (0.478 s) + ½ (0 m/s²) (0.478 s)²

Δx = 1.10 m

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Answer:

2.66m/s

Explanation:

information we have

power: 65W

work per step per kilogram: 0.60J

mass: 61kg

length of a running step: 1.5m

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the formula for power is:

P=\frac{W}{t}

where W is the work and t is time.

time is also defined as: t=\frac{distance}{velocity}=\frac{d}{v}

so substituting this into the formula for power we get:

P=\frac{W*v}{d}

where v is the velocity we are looking for, d is the distance per step: d=1.5m, W is the work per step and P is power P=65W.

we know that the work per step per kilogram is:

0.60J

so to find the work per step of his whole body we need to multiply the 0.60J by the 61 kilograms of his mas:

W=0.60J*61kg\\W=36.6Jthis is the work per step of the person.

So now we can calculate the velocity using the formula for power

P=\frac{W*v}{d}

clearing for v:

v=\frac{P*d}{W}\\

and substituting known values:

v=\frac{(65W)(1.5m)}{36.6J}= 2.66m/s

6 0
3 years ago
What is the mass of a bowling ball if it has a weight of 80N?
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wich following is not use of doppler effect? a, radar b, astronomy c, energy transmission d, blood floe measurment​
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3 years ago
You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 13-m-hi
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Answer:

22.15 N/m

Explanation:

As we know potential energy = m*g*h

Potential energy of spring = (1/2)kx^2

m*g*h = (1/2)kx^2

Substituting the given values, we get -  

(400)*(9.8)*(10) = (0.5)*(k)*(2.0^2)

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For safety reasons, this spring constant is increased by 13 % So the new spring constant is  

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