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ivann1987 [24]
3 years ago
5

A satellite moves in a circular orbit a distance of 1.6×10^5 m above Earth's surface. (radius of Earth is 6.38 x 10^6m and its m

ass is 5.98 x 10^24 kg). Determine the speed of the satellite.
Physics
1 answer:
Rashid [163]3 years ago
5 0

Answer:

The speed of the satellite is 7809.52 m/s        

Explanation:

It is given that,

Radius of Earth, r=6.38\times 10^6\ m

Mass of earth, M=5.98\times 10^{24}\ kg

A satellite moves in a circular orbit a distance of, d=1.6\times 10^5\ m  above Earth's surface.

We need to find the speed of the satellite. It is given by :

v=\sqrt{\dfrac{GM}{R}}

R = r + d

R=(6.38\times 10^6\ m+1.6\times 10^5\ m)=6540000\ m

So, v=\sqrt{\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 5.98\times 10^{24}\ kg}{6540000\ m}}

v = 7809.52 m/s

So, the speed of the satellite is 7809.52 m/s. Hence, this is the required solution.

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A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of
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The field strength needed to produce a 24.0 V peak emf is 0.73T.

To find the answer, we need to know about the expression of emf.

What's the expression of peak emf produced in a rotating rectangular loops?

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  • N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²
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A battery powered device makes use of direct current (DC) electric power from a battery, while the power normally given out at an electrical outlet comes as an alternating current (AC) electric power source.

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