Bottom of the distillation flask
Explanation:
The solid in the mixture to be separate would be found at the bottom of the distillation flask.
Distillation is a separation technique for differentiating the components of mixtures based on the differences in their boiling points.
- Distillation is used to recover solvents from solution.
- The solutes are then left behind in the flask as the solvent boils out as vapor.
- The solution is boiled in a distillation flask to vaporize the solvent.
- The vapor is made to condense back into liquid by means of a condenser.
- The pure liquid called distillate is collected in the receiver.
- The solute which is the solid remains in the distillation flask
learn more:
Heterogeneous mixtures brainly.com/question/1446244
Pure substances brainly.com/question/1832352
#learnwithBrainly
Answer:
Work out = 28.27 kJ/kg
Explanation:
For R-134a, from the saturated tables at 800 kPa, we get
= 171.82 kJ/kg
Therefore, at saturation pressure 140 kPa, saturation temperature is
= -18.77°C = 254.23 K
At saturation pressure 800 kPa, the saturation temperature is
= 31.31°C = 304.31 K
Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.
Thus, 
= = 171.82 kJ/kg
We know COP of heat pump
COP = 
= 
= 6.076
Therefore, Work out put, W = 
= 171.82 / 6.076
= 28.27 kJ/kg
the answer is B! it would continue to expand.....just took the test XD
Answer:
20 m/s
Explanation:
Recall that one of the equations of motions can be written:
v = u + at, (also see attached for reference)
Where,
v = final speed (we are asked to find this)
u = initial speed = 0 (because it starts from rest)
t = time taken = 5s
We simply substitute the given values into the equation:
v = u + at
v = 0 + (4)(5)
v = 20 m/s
Answer: 1.91*10^8 N/m²
Explanation:
Given
Radius of the steel, R = 10 mm = 0.01 m
Length of the steel, L = 80 cm = 0.8 m
Force applied on the steel, F = 60 kN
Stress on the rod, = ?
Area of the rod, A = πr²
A = 3.142 * 0.01²
A = 0.0003142
Stress = Force applied on the steel/Area of the steel
Stress = F/A
Stress = 60*10^3 / 0.0003142
Stress = 1.91*10^8 N/m²
From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²
