1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alja [10]
3 years ago
6

ممكن حل بسرعة please help ​

Physics
2 answers:
aleksley [76]3 years ago
7 0
I don’t understand anything but Good luck u got it!!!!
jarptica [38.1K]3 years ago
3 0

Answer:

I could help but i dont speak or understand a word of Arabic im so sorry.

Explanation:

You might be interested in
The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminu
antiseptic1488 [7]
<span>C)<span>a powerful magnet.

</span></span>
8 0
3 years ago
Read 2 more answers
When a nerve cell depolarizes, charge is transferred across the cell membrane, changing the potential difference. For a typical
laila [671]

Answer:

I = 18 x 10⁻⁹ A = 18 nA

Explanation:

The current is defined as the flow of charge per unit time. Therefore,

I = q/t

where,

I = Average Current passing through nerve cell

q = Total flow of charges through nerve cell

t = time period of flow of charges

Here, in our case:

I = ?

q = (9 pC)(1 x 10⁻¹² C/1 pC) = 9 x 10⁻¹² C

t = (0.5 ms)(1 x 10⁻³ s/1 ms) = 5 x 10⁻⁴ s

Therefore,

I = (9 x 10⁻¹² C)/(5 x 10⁻⁴ s)

<u>I = 18 x 10⁻⁹ A = 18 nA</u>

6 0
3 years ago
How much kinetic energy does a moving 100 kg object have if it is moving at 5 m/s?
Vesnalui [34]

Answer:

The object has 1250 Joules of Kinetic Energy.

Explanation:

Kinetic Energy = \frac{1}{2}mass*velocity²

KE = \frac{1}{2}mv²

KE = \frac{1}{2}(100kg)(5m/s)²

KE = \frac{1}{2}(100kg)(25m/s²)

KE = 1250\frac{kg}{m/s^2}

KE = 1250J

4 0
3 years ago
Can someone tell me everything they know about mechanical waves and ASAP, please!?!?!?
oksano4ka [1.4K]

Answer:

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. While waves can move over long distances, the movement of the medium of transmission—the material—is limited. Therefore, the oscillating material does not move far fro

Explanation:

6 0
2 years ago
Read 2 more answers
A 58.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 140 m/s from the top of a cliff
strojnjashka [21]

(a) 6.43\cdot 10^5 J

The total mechanical energy of the projectile at the beginning is the sum of the initial kinetic energy (K) and potential energy (U):

E=K+U

The initial kinetic energy is:

K=\frac{1}{2}mv^2

where m = 58.0 kg is the mass of the projectile and v=140 m/s is the initial speed. Substituting,

K=\frac{1}{2}(58 kg)(140 m/s)^2=5.68\cdot 10^5 J

The initial potential energy is given by

U=mgh

where g=9.8 m/s^2 is the gravitational acceleration and h=132 m is the height of the cliff. Substituting,

U=(58.0 kg)(9.8 m/s^2)(132 m)=7.5\cdot 10^4 J

So, the initial mechanical energy is

E=K+U=5.68\cdot 10^5 J+7.5\cdot 10^4 J=6.43\cdot 10^5 J

(b) -1.67 \cdot 10^5 J

We need to calculate the total mechanical energy of the projectile when it reaches its maximum height of y=336 m, where it is travelling at a speed of v=99.2 m/s.

The kinetic energy is

K=\frac{1}{2}(58 kg)(99.2 m/s)^2=2.85\cdot 10^5 J

while the potential energy is

U=(58.0 kg)(9.8 m/s^2)(336 m)=1.91\cdot 10^5 J

So, the mechanical energy is

E=K+U=2.85\cdot 10^5 J+1.91 \cdot 10^5 J=4.76\cdot 10^5 J

And the work done by friction is equal to the difference between the initial mechanical energy of the projectile, and the new mechanical energy:

W=E_f-E_i=4.76\cdot 10^5 J-6.43\cdot 10^5 J=-1.67 \cdot 10^5 J

And the work is negative because air friction is opposite to the direction of motion of the projectile.

(c) 88.1 m/s

The work done by air friction when the projectile goes down is one and a half times (which means 1.5 times) the work done when it is going up, so:

W=(1.5)(-1.67\cdot 10^5 J)=-2.51\cdot 10^5 J

When the projectile hits the ground, its potential energy is zero, because the heigth is zero: h=0, U=0. So, the projectile has only kinetic energy:

E = K

The final mechanical energy of the projectile will be the mechanical energy at the point of maximum height plus the work done by friction:

E_f = E_h + W=4.76\cdot 10^5 J +(-2.51\cdot 10^5 J)=2.25\cdot 10^5 J

And this is only kinetic energy:

E=K=\frac{1}{2}mv^2

So, we can solve to find the final speed:

v=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(2.25\cdot 10^5 J)}{58 kg}}=88.1 m/s

4 0
3 years ago
Other questions:
  • Two ropes have equal length and are stretched the same way. The speed of a pulse on rope 1 is 1.4 times the speed on rope 2. Par
    11·1 answer
  • Which statement is always true about objects which exert gravitational force on each other? A. They are a very large size. B. Th
    12·1 answer
  • Are passing through optical Centre deviate why ​
    9·1 answer
  • What do all objects with mass produce ?
    12·1 answer
  • a student coils a copper wire around a bar magnet what action will cause a device to generate electricity
    14·1 answer
  • What energy transformation takes place when an object is pushed up an inclined plane?
    10·2 answers
  • True or false if an object has energy it must be moving
    11·2 answers
  • What is the resistance of al lamp that allows a current of 10 amps with 120 volts
    6·1 answer
  • How the different types of waves are form and how the waves travel
    9·1 answer
  • Convert 800 cm to meters.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!