Answer:
The average acceleration is 8.06 m/s².
Explanation:
It is given that,
Initial speed of the jet, u = 120 mph = 176 ft/s
Final velocity of the jet, v = 30 mph = 44 ft/s
Distance, d = 1800 ft
We need to find the average acceleration required of the airplane during braking. It can be calculated using third law of motion as :
a = acceleration
So, the average acceleration required of the airplane during braking is -8.06 ft/s². Hence, this is the required solution.
The lack of a subscript after the 0 means that there is only one oxygen (0).
There are 2 hydrogen molecules and 1 oxygen molecules
hope this helps
<h2>
Answer: 469 feet</h2>
Explanation:
This problem is a good example of Vertical motion, where the main equation for this situation is:
(1)
Where:
is the height of the stone at 6s (the value we want to find)
is the initial height of the stone
is the initial velocity of the stone
is the time at which we need to find the height
is the acceleration due to gravity
Having this clear, let's find from (1):
(2)
Finally:
This is the height of the stone at t=6s
Answer:
32.6mm
Explanation:
Using area of a sphere(bulb) = 4πr²
So A is proportional to radius²
So the Energy will be proportional to r²
But 120/80 = 1.5 is the energy factor so
Using
1.5/d² = 1/r²
1.5/40²= 1/r^2
r = √( 40²/ 1.5)
r = 32.6m
<span>If there isn't any force then the normal contact force will be
N=m*g=7.5*9.81=73.58N
which is 73.58-23=50.58N less
so, there the person must pull at 23 degree upward
break down the tension in two components, vertical and horizontal.
vertical tension= 50.58=T*sin23
T=50.58/sin23=129.45N</span>
