Answer:
<em>It matters because crystalline and amorphous materials have different properties. The arrange affects the melting point (defined in crystals and a larger range in amorphous) and shape (geometrical in crystals, no geometrical in amorphous). </em>
Explanation:
The particles that compose a solid material are held in place by strong tractive forces between them when we analyze solids we consider the position of the atoms (molecules or ions) rather than their motion (which is important in liquids and gases). This positioning can be arranged in two general ways:
- Crystalline solids have internal structures that in turn lead to distinctive flat surfaces or face, these faces intersect at angles that are characteristic of the substance, crystals tend to have sharp, well defined and high melting points because of the same distance from the same number and type of neighbors. They generally have geometric shapes, some examples are diamonds, metals, salts.
- Amorphous solids produce irregular or curved surfaces when broken and they have poorly defined patterns when exposed to x rays because of their irregular array. In contrast with crystal solids, amorphous solids soften over a wide temperature range due to the different amounts of thermal energy needed to overcome different interactions. Some examples of these solids are gels, plastics, and some polymers.
I hope you find this information useful and interesting! Good luck!
Due to the law of conservation of momentum, the force exerted on the mallet is equal and opposite to the force exerted on the ball, so the answer is C.
Answer:
the velocity (magnitude and direction) of the ball) just before the collision is 
The velocity (magnitude and direction) of the ball) just after the collision is 
Explanation:
According to the law of conservation of energy;
Thus; the velocity (magnitude and direction) of the ball) just before the collision is
Since, Air resistance is negligible, and the collision is elastic.
The equation for the conservation of momentum and energy can be expressed as:
![v_f = [\frac{m_1 -m_2}{m_1+m_2}]v_i\\\\v_f = [\frac{m_{ball} -m_{block}}{m_{ball}+m_{block}}]v_i\\\\v_f = [\frac{1.6 -2.5}{1.6+2.5}]*5.144\\\\](https://tex.z-dn.net/?f=v_f%20%3D%20%5B%5Cfrac%7Bm_1%20-m_2%7D%7Bm_1%2Bm_2%7D%5Dv_i%5C%5C%5C%5Cv_f%20%3D%20%20%5B%5Cfrac%7Bm_%7Bball%7D%20-m_%7Bblock%7D%7D%7Bm_%7Bball%7D%2Bm_%7Bblock%7D%7D%5Dv_i%5C%5C%5C%5Cv_f%20%3D%20%5B%5Cfrac%7B1.6%20-2.5%7D%7B1.6%2B2.5%7D%5D%2A5.144%5C%5C%5C%5C)
The velocity (magnitude and direction) of the ball) just after the collision is
It measures<span> the relative humidity in the atmosphere through the use of two thermometers. The first, a dry bulb thermometer, is used to </span>measure<span> the temperature by being exposed to the air. The second, a wet bulb thermometer,</span>measures<span> temperature by having the bulb dipped in a liquid.</span>
