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Crank
3 years ago
13

The study of alternating electric current requires the solutions of equations of the form i equals Upper I Subscript max Baselin

e sine 2 pi ft comma for time t in​ seconds, where i is instantaneous current in​ amperes, Imax is maximum current in amperes and f is the number of cycles per second. Find the least positive value of​ t, given the following data. i=180, Imax=200, f=50
Physics
1 answer:
KiRa [710]3 years ago
8 0

Answer:

Explanation:

i = Imax sin2πft

given i = 180 , Imax = 200 , f = 50  , t = ?

Put the give values in the equation above

180 = 200 sin 2πft

sin 2πft = .9

sin2π x 50t = .9

sin 360 x 50 t = sin ( 360n + 64 )

360 x 50 t = 360n + 64

360 x 50 t =  64 ,  ( putting n = 0 for least value of t )

18000 t = 64

t = 3.55 ms  .

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flat sheet is in the shape of a rectangle with sides of lengths 0.400 mm and 0.600 mm. The sheet is immersed in a uniform electr
Ksenya-84 [330]

Answer:

6.29591\times 10^{-6}\ N/C^2

Explanation:

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\phi=EAcos\theta

A = Area

A=0.4\times 10^{-3}\times 0.6\times 10^{-3}

E = Electric field = 76.7 N/C

Angle is given by

\theta=90-20\\\Rightarrow \theta=70^{\circ}

\phi=76.7\times 0.4\times 10^{-3}\times 0.6\times 10^{-3}\times cos70\\\Rightarrow \phi=6.29591\times 10^{-6}\ N/C^2

The flux through the sheet is 6.29591\times 10^{-6}\ N/C^2

6 0
3 years ago
A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial spe
dezoksy [38]

Answer:

the magnitude of the average contact force exerted on the leg is  3466.98 N

Explanation:

Given the data in the question;

Initial velocity of hand v₀ = 5.25 m/s

final velocity of hand v = 0 m/s

time interval t = 2.65 ms = 0.00265 s

mass of hand m = 1.75 kg

We calculate force on the hand F_{hand

using equation for impulse in momentum

F_{hand × t = m( v - v₀ )

we substitute

F_{hand × 0.00265  = 1.75( 0 - 5.25 )

F_{hand × 0.00265  = 1.75( - 5.25 )

F_{hand × 0.00265  = -9.1875

F_{hand = -9.1875 / 0.00265  

F_{hand = -3466.98 N

Next we determine force on the leg F_{leg

Using Newton's third law of motion

for every action, there is an equal opposite reaction;

so, F_{leg = - F_{hand

we substitute

F_{leg = - ( -3466.98 N )

F_{leg = 3466.98 N

Therefore, the magnitude of the average contact force exerted on the leg is  3466.98 N

5 0
3 years ago
A boulder with a mass of 50 kg, sits on a cliff that is 50 m high. The boulder is pushed off of the cliff. How much kinetic ener
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50 +50 =100 Since it’s sitting on a 50m cliff that’s high with a mass of 50 kg it would be adding because once it goes down it’s adding speed
8 0
3 years ago
Volume equals 4÷3 times pi times nine to the power of 3
Tcecarenko [31]

Answer:

V=972π

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4 0
2 years ago
Which of the following is considered plagiarism?
-Dominant- [34]

Answer:

Copying materials from a source text, supplying proper documentation, but leaving out quotation marks

Explanation:

Plagiarism is when you take somebody's ideas and write them off as your own without giving them credit.

8 0
3 years ago
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