Question

How many moles of gas molecules will be present in 5000 L of air at STP?

Answer 1

5000L • 1 mole /22.4L so approximately 223 moles

Answer 2

Answer:

n = 223 mol

Explanation:

Given data

P = 1.00 atm (standard pressure)

T = 273.15 K (standard temperature)

n = ?

R = 0.08206 atm.L/mol.K (ideal gas constant)

V = 5000 L

We can find the moles of gas molecules using the ideal gas equation.

P × V = n × R × T

1.00 atm × 5000 L = n × (0.08206 atm.L/mol.K) × 273.15 K

n = 223 mol