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lutik1710 [3]
3 years ago
9

A chemist measures the energy change

Chemistry
1 answer:
Flauer [41]3 years ago
8 0

<u>Answer:</u>

<u>For (1):</u> The correct option is (a)

<u>For (2): </u>The correct option is (a) and 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts.

<u>Explanation:</u>

There are 2 types of reactions that are classified based on enthalpy change:

<u>Endothermic reactions:</u> These are the reactions where heat is absorbed by the reaction. The change in enthalpy of the reaction, \Delta H_{rxn} is positive for these reactions.

<u>Exothermic reactions:</u> These are the reactions where heat is released by the reaction. The change in enthalpy of the reaction, \Delta H_{rxn} is negative for these reactions.

  • <u>For (1):</u>

For the given chemical reaction:

2NH_3(g)\rightarrow N_2(g)+3H_2(g);Delta H=160kJ

As the change in enthalpy or heat of the reaction is positive. Thus, the reaction is an endothermic reaction because heat is absorbed by the reaction.

  • <u>For (2):</u>

When ammonia reacts, some amount of heat will be absorbed by the reaction. Thus, we can say the heat will be absorbed.

The number of moles is calculated by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of ammonia = 70.9 g

Molar mass of ammonia = 17 g/mol

Using equation 1:

\text{Moles of ammonia}=\frac{70.9g}{17g/mol}=4.17mol

By stoichiometry of the reaction:

If 2 mole of ammonia reacts, the heat absorbed is 160 kJ

So, if 4.17 moles of ammonia reacts, the heat absorbed will be = \frac{160kJ}{2mol}\times 4.17mol=333.6kJ

Hence, 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts

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charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
A reaction produces 0.883 moles of H₂O. How many molecules are produced?
prisoha [69]
The answer is 5.32 × 10²³ molecules

<span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance:
</span>6.023 <span>× 10²³ units per 1 mole

We have 0.883 moles.
If 1 mole has </span>6.023 × 10²³ molecules, 0.883 moles will have x molecules:
1 mole : 6.023 × 10²³ molecules = 0.883 moles : x

x = 6.023 × 10²³ molecules * 0.883 moles : 1 mole = 5.32 × 10²³ molecules
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3 years ago
Which activity performed by a chemist is primarily based on an understanding of physics?
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Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o
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Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
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In an exothermic reaction, energy is blank the surroundings.
S_A_V [24]

Answer: released to; absorbed from

- In an exothermic reaction, energy is released to the surroundings.

- In an endothermic reaction, energy is absorbed from the surroundings.

Explanation:

An exothermic reaction is a chemical reaction that occurs spontaneously and brings about the release of energy to the surroundings. Hence, the reacting vessel feels hot as the reaction proceeds.

An endothermic reaction, on the other hand, does not occur spontaneously and proceed only when energy is absorbed from the surroundings. Hence, the reacting vessel feels cold as the reaction proceeds.

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