<span>first what's the mass of 1 mole of CH3OH
</span>C = 12
H3 = 3x1 = 3
O = 16
H =1
<span>Total 32g So we know 6.02x10^23 molecules weigh 32g
</span> 1 molecule weighs 32/6.02x10^23 g so 9.38*10^24 <span>molecules weighs
</span>9.38x10^24 x (32/6.02x10^23=<span>505g (to 3 sig figs</span>
Answer:
Explanation:
Hello,
In this case, since the solution is formed by sodium chloride and water, we understand that for one mole of solution, we have 0.132 moles of sodium chloride and 0.868 moles of water, therefore, by using their molar masses we can compute their masses in the solution:
Thereby, we can compute the weight/weight percent as follows:
So we use the previously computed masses:
Best regards.
Answer: The value of for the given reaction is .
Explanation:
The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.
It is denoted by the symbol .
For example,
The expression for of this reaction is as follows.
So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of for the given reaction.
Thus, we can conclude that the value of for the given reaction is .
the most important methods are A and B