1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
allochka39001 [22]
3 years ago
13

Write a balanced overall reaction from these unbalanced half-reactions sn and ag

Chemistry
1 answer:
loris [4]3 years ago
8 0
Balance each one by adding electrons to make the charges on both sides the same:

Sn--> Sn2+ + 2 e-
Ag+ + 1 e- --> Ag

Now, you have to have the same number of electrons in the two half-reactions, so multiply the second one by 2 to get:

2 Ag+ + 2 e- --> 2 Ag

Now, just add the two half reactions together, cancelling anything that's the same on both sides:

2 Ag+ + Sn --> Sn2+ + 2 Ag

And you're done.
You might be interested in
What is the position of the earth, moon, and sun during a new moon?
Anastasy [175]

Answer:When the Moon is between the Earth and the Sun, the bright side of the Moon is facing away from the Earth, and we have a New Moon.

Explanation:

6 0
2 years ago
Read 2 more answers
If an increase in temperature accompanies a reaction, what occurred?
son4ous [18]
I believe the correct response would be A. Energy being absorbed, as temperature increase must for instance occur for the reaction to occur, this increase in temperature for the reacting substances indicates energy being absorbed as the reaction proceeds.
3 0
3 years ago
Read 2 more answers
Calculate the number of moles in 18.5 g of aluminum thiosulfate, Al2(S2O3)3
alisha [4.7K]

Answer:

0.05 mol

Explanation:

Moles = Mass / Mr (Relative formula mass)

Ar of aluminium = 27

Ar of sulphur = 32

Ar of oxygen = 16

Mr of Al2(S2O3)2 = (27×2)+((32×2)×3)+((16×3)×3)= 390

Moles = 18.5g / 390

Moles = 0.05 mol

5 0
3 years ago
Use the balanced equation below to answer the question that follows
natta225 [31]
It’s c hdjdkdmnfvdheidk
4 0
3 years ago
What is the Ea for the exothermic reaction A)332.6 kJ B)-85.1 kJ C)251.0 kJ D) -251.0 kJ
Lina20 [59]

Answer:

Option C. 251 kJ

Explanation:

The activation energy (Ea) of a given reaction is the minimum energy that must be overcomed for reactant to proceed to product.

The activation energy (Ea) can be obtained from an energy profile diagram by simply calculating the difference between the energy of the activation complex (i.e the peak) and the energy of the reactant.

Thus, we can obtain the activation energy for the reaction above as follow:

Activation complex = 332.6 kJ

Energy of reactant = 81.6 kJ

Activation energy =?

Activation energy = Activation complex – Energy of reactant

Activation energy = 332.6 – 81.6

Activation energy = 251 kJ

Therefore, the activation energy of the reaction is 251 kJ

5 0
4 years ago
Other questions:
  • An electrochemical cell is powered by the half reactions shown below.
    8·1 answer
  • Compare the vapor pressure curves of 1-butene and 1-heptene. Explain your reasoning.
    14·2 answers
  • In a chemical reaction, the difference between the potential energy of the products and the potential energy of the reactants is
    12·2 answers
  • 2. A student measures the mass of a substance as 1.7132 kg and its volume 1 point
    9·1 answer
  • Noah studied different systems in the human body. Which best describes a function of the veins in the circulatory system?
    7·1 answer
  • PLEASE ANSWER...........WILL MARK BRAINLIEST!!!!!!!
    10·1 answer
  • Ricardo wants to determine the length of a strip of zinc metal. What is the SI unit for length?
    15·2 answers
  • What was the physical property used by mendleev in creating his periodic table.​
    14·1 answer
  • g The rate of a reaction typically increases as the temperature increases because: The rate of a reaction typically increases as
    15·1 answer
  • What is the complete word equation for incomplete combustion for methane
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!