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Zina [86]
3 years ago
9

PLEASE HELP

Physics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

1250

Explanation:

just took the test

wel3 years ago
6 0
The answer is 1,250 W.  
Solution: 
To use the power rule P = VI, we need to know both the current I flowing through the resistor, and the voltage V across the resistor. But by substituting Ohm’s law I = V/R, we can also express the power rule equation P = VI as 
     P = R (V/R)^2 = R V^2 / R^2 = V^2 / R 
We can now substitute the values for the resistance and voltage into the equation to get the power rating: 
     P=V^2 / R = (120)^2 / 11.5 = 1252.17 Watts ≈ 1250 Watts 
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1. Calculate the power it takes for a 583 N student to climb up1.5 m stairs in 2.1 seconds. (find work first!)GivenFormulaSubsti
Tanzania [10]

Given data

*The given force is F = 583 N

*The given distance is s = 1.5 m

*The given time is t = 2.1 s

The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

P=\frac{F\mathrm{}s}{t}

Substitute the known values in the above expression as

\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W

3 0
1 year ago
An increase of 50 dB increases the sound intensity by a factor of
Artemon [7]

A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .


5 0
4 years ago
If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Oksanka [162]

The fraction of the tensile strength which is the stress on the femur is 1.4%.

<h3>What is Tensile strength?</h3>

This is defined as the amount of load or stress that a material can handle before it stretches and breaks.

The femur which is located in the thigh is the largest bone in the body and it exerts a fraction of 1.4% tensile strength through the stress encountered on the femur when the man stands with one leg.

Read more about Tensile strength here brainly.com/question/25748369

5 0
2 years ago
A roller coaster starts from rest at point A. What is its speed at point C if the track is frictionless.
OleMash [197]
At A, coaster is only associated with potential energy.
At B, coaster is associated with kinetic as well as potential energy.
Since the track is frictionless, no energy will be lost when coaster reaches from point A to point B. Therefore, according to conservation of energy, total energy at A should be equal to total energy at B.
Total energy at A = mgh = mg(12) 
Total energy at B = mgh+ mv²/2 = mg(2) + mv²/2
∴12mg = 2mg + mv²/2
∴(12g-2g)×2 = v²
∴v² = 20g
∴v = 14m/s.

Again conserving energy at points B and C.
Total energy at B = 2mg + m(14)²/2 
Total energy at C = 4mg + mv²/2
∴2mg + m(14²)/2 = 4mg + mv²/2
Solving this you get,
v = 12.52 m/s.
Therefore, speed of roller coaster at point C is 12.52 m/s.
8 0
4 years ago
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency o
GrogVix [38]

Wave speed = (wavelength) x (frequency)

Wave speed = (0.5 m) x (2 /sec)

<em>Wave speed = 1 m/s</em>

4 0
3 years ago
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