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Zina [86]
3 years ago
9

PLEASE HELP

Physics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

1250

Explanation:

just took the test

wel3 years ago
6 0
The answer is 1,250 W.  
Solution: 
To use the power rule P = VI, we need to know both the current I flowing through the resistor, and the voltage V across the resistor. But by substituting Ohm’s law I = V/R, we can also express the power rule equation P = VI as 
     P = R (V/R)^2 = R V^2 / R^2 = V^2 / R 
We can now substitute the values for the resistance and voltage into the equation to get the power rating: 
     P=V^2 / R = (120)^2 / 11.5 = 1252.17 Watts ≈ 1250 Watts 
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A 16.0 kg child on roller skates, initially at rest, rolls 2.0 m down an incline at an angle of 20.0° with the horizontal. If th
enyata [817]

The kinetic energy of the child at the bottom of the incline is 106.62 J.

The given parameters:

  • <em>Mass of the child, m = 16 kg</em>
  • <em>Length of the incline, L = 2 m</em>
  • <em>Angle of inclination, θ = 20⁰</em>

The vertical height of fall of the child from the top of the incline is calculated as;

sin(20) = \frac{h}{2} \\\\h = 2 \times sin(20)\\\\h = 0.68 \ m

The gravitational potential energy of the child at the top of the incline is calculated as;

P.E = mgh\\\\P.E = 16 \times 9.8 \times 0.68\\\\P.E = 106.62 \ J

Thus, based on the principle of conservation of mechanical energy, the kinetic energy of the child at the bottom of the incline is 106.62 J since no energy is lost to friction.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

7 0
2 years ago
If an object has a kinetic energy of 30 j and mass of 34kg how fast is the object moving ?
cricket20 [7]

Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.

Ek = mv^2 / 2 — multiply both sides by 2

2Ek = mv^2 — divide both sides by m

2Ek / m = V^2 — switch sides

V^2 = 2Ek / m — plug in values

V^2 = 2*30J / 34kg

V^2 = 60J/34kg

V^2 = 1.76 m/s — sqrt of both sides

V = sqrt(1.76)

V = 1.32m/s (roughly)

3 0
3 years ago
According to the law of conservation of energy, mechanical energy can be changed to heat energy.
Leno4ka [110]

Answer:

The answer to this question is given below in this explanation section.

Explanation:

                     " law of conservation of energy"

The law of conservation of energy states that energy can neither be created nor destroyed only converted from one form of energy into another.This mean that a system always has a same account of a energy,unless it is added from the outside.This is particularly confusing in the case of non conversation forces,where energy is converted from ,mechanical energy into thermal energy.but the overall energy does remain the same.The only way to use energy is to transform energy from one form to another.

The amount of energy in any system than it is determined by the following equation.

Ut=Ui +W+Q

  • Ut is the total internal energy of a system.
  • Ui is the initial internal energy of a system.
  • W is the work done by or on the system.
  • Q is the heat added to or removed by the system.

It is also possible to determined the change in internal energy of the system using the equation.

ΔU=W+Q

The mechanical energy of a system increases provided their is no loss of energy due to friction.The energy would transform to kinetic energy when the speed is increasing.Te mechanical energy of a system remain constant provided their is no loss of energy due to friction.

The law of conversation of energy which say that in a closed system total energy is conserved that is it constant.

KE1 + PE1=KE2+PE2

 

8 0
3 years ago
a 65 kg skater at rest on a frictionless rink throws a 2 kg ball, giving the ball a velocity of 7 m/s. What is the velocity of t
gayaneshka [121]
The answer to your question is 33
8 0
3 years ago
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

7 0
3 years ago
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