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abruzzese [7]
3 years ago
8

Arnold makes a chart to summarize what happens when light interacts with matter and is reflected. Which best describes Arnold’s

error? a. In specular reflection, reflected rays move in the same direction. b. In scattering, short wavelengths are scattered the least. c. In diffuse reflection, reflected rays move in the same direction. d. The law of reflection is not followed in scattering.
Physics
2 answers:
Svetllana [295]3 years ago
4 0

Answer:

The correct answer is d.

Explanation:

The law of reflection states that an incident ray on a reflecting surface will be reflected at an angle equal to the angle of incidence, where each angle is measured concerning the line normal to the surface.

In the graph that indicates what happens when light interacts with matter and is reflected, you make the mistake of not following the law of reflection in scattering.

Have a nice day!

Leokris [45]3 years ago
3 0

Answer:

D) The law of reflection is not followed in scattering

Explanation:

Just took the unit review on edgen and got this right

Have a nice day :)

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Which substances resist pH changes? <br> Acids<br> Hydrogen ions<br> Buffers<br> Bases
Vikki [24]

The correct choice is Buffers.

Buffers contains both acids and bases in equilibrium.when base is added to buffers, they adjust the pH value by releasing hydrogen ions.when acid is added to buffers, they adjust the pH value by consuming hydrogen ions. hence these substances resist any change in their pH value by releasing or absorbing hydrogen ions.This process keeps the pH value constant.

6 0
3 years ago
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Name 2 common methods of polymerization.
navik [9.2K]

Answer: Addition polymerization & Condensation polymerization

6 0
3 years ago
A kid on a playground swing makes a complete to-and-fro swing each 2 seconds.
sashaice [31]

Answer:

The frequency of the swing: 1/2 Hertz

The period is: 2 Seconds

Explanation:

The time the kid takes to make a complete to-and-fro swing = 2 seconds

The period, T, is the time it takes to make one complete cycle of an oscillatory motion, therefore, we have;

The frequency, f, is the number of cycles completed each second, therefore, we have;

The time for 1 cycle = 2 seconds

2 seconds = 1 cycle

Dividing both sides by 2 gives;

2/2 seconds = 1/2 cycles

2/2 = 1

In 2/2 = 1 seconds The number of cycles completed = 1/2 cycles

Therefore, the number of cycles completed per (one) second = 1/2 cycles

Therefore the frequency of the swing, f = 1/2 cycle/seconds = 1/2 Hertz

The period, T, is the time it takes to complete one to-and-fro swing which is one cycle which is 2 seconds

Therefore, the period is 2 Seconds.

4 0
3 years ago
Consider a loop of wire with a resistor. In the same plane, (with switch S closed) a long wire has a current I flowing from left
Ulleksa [173]

Solution :

The given figure is a loop of a wire with a resistor.

When the switch S is closed for long time and is suddenly opened, the direction of the induced current can be find out by using the rule of right hand screw. According to the right hand screw rule, the direction of the magnetic field at the loop is in the direction that points outwards. The strength of the current rapidly decreases as it is switch off and the magnetic flux that is linked with the loop wire will also decrease.

According to the Lenz's law, the direction of the induced current must be such $\text{that it opposes}$ the decrease in the magnetic flux.  It means the direction of the magnetic field must be outwards and also normal to the plane of the screen. The direction of the induced anti clockwise or from right to left in the resistance.

6 0
3 years ago
Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha
Ivan

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a   it is always zero

b  0

c  \eta  =  -\epsilon _o E

Explanation:ss

Here the  net charge is  on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area  which implies that the charge density is dependent on the net charge  so this  means that the charge density inside the conductor is zero

 

Generally the direction of electric field this from the  positive charge to the negative charge  so from the question we can deduce  that the negative charge is located on the surface of the conductor

    So We can mathematically define the charge density on the surface of the electric field as

             ∮E \cdot dA =  \frac{-Q}{\epsilon _o}

Where E is the electric field

          dA change in unit area

           -Q is the negative charge

          \epsilon _o  is the permittivity of free space

So

          EA  =  \frac{-Q}{\epsilon _o }

           \frac{Q}{A}  =  -\epsilon _o E

          \eta  =  -\epsilon _o E

Where \eta is the charge density

   

8 0
3 years ago
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