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2 years ago

What is temperature?

Physics

1 answer:

hammer [34]2 years ago

5 0

The term temperature has to do with the measure of an object's "hotness".

<h3>What is temperature?</h3>

The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.

Succinctly put, the term temperature has to do with the measure of an object's "hotness".

Learn more about temperature:brainly.com/question/7510619

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Arysha enjoys playing lacrosse on the school team. Suppose Arysha throws a lacrosse ball with a force of 6 N, and the resulting

olasank [31]

Answer:

$Mass = 0.14kg$

Explanation:

Given

$Force = 6N$

$Acceleration = 43m/s^2$

Required

Determine the mass of the ball

This question will be answered using Newton's second law of motion.

Which states that

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$6N = Mass * 43m/s^2$

Make Mass the subject

$Mass = \frac{6N}{43m/s^2}$

$Mass = 0.13953488372$

$Mass = 0.14kg$ --- (approximated)

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3 years ago

It takes a car 1.75 h to go from mile marker 10 to mile marker 115. What is the average speed of the car? Someone who took this

givi [52]

The distance from mile-mark 10 to mile-mark 115 is (115-10) = 105 miles.

Speed = (distance covered) / (time to cover the distance) .

Speed = (105 miles) / (1.75 hours)

Speed = (105/1.75) (mi/hr)

<em>Speed = 60 mph</em> (B)

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4 years ago

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Three mountain climbers set out to climb a mountain from the same altitude and all arrive at the same location at the top. Mount

vampirchik [111]

C did the most effort, but A walked the longest, so a reasonable answer is that they all did the same amount of work, as B simply mediates.

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3 years ago

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In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s. Ignore fr

spin [16.1K]

Answer:

a) $v_p=9.35m/s$

Explanation:

From the question we are told that:

Open cart of mass $M_o=50.0 kg$

Speed of cart $V=5.00m/s$

Mass of package $M_p=15.0kg$

Speed of package at end of chute $V_c=3.00m/s$

Angle of inclination $\angle =37$

Distance of chute from bottom of cart $d_x=4.00m$

Generally the equation for work energy theory is mathematically given by

$\frac{1}{2}mu^2+mgh=\frac{1}{2}mv_p^2$

Therefore

$\frac{1}{2}u^2+gh=\frac{1}{2}v_p^2$

$v_p=\sqrt{2(\frac{1}{2}u^2+gh)}$

$v_p=\sqrt{2(\frac{1}{2}v_c^2+gd_x)}$

$v_p=\sqrt{2(\frac{1}{2}(3)^2+(9.8)(4))}$

$v_p=9.35m/s$

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3 years ago

At the circus, a 100.-kilogram clown is fired at 15 meters per second from a 500.- kilogram cannon. What is the recoil speed of

photoshop1234 [79]

The recoil velocity of cannon is (4) 5.0 m/s

Explanation:

We can find the recoil velocity from the law of conservation of momentum.

The recoil velocity is velocity of body 2 after release of body 1, i.e. velocity of cannon after release of clown.

Let v2 be cannon's velocity, v1 be clown's velocity given = 15 m/sec

m1 be clown's mass = 100kg and m2 be cannon's mass given = 500kg.

So recoil velocity of cannon v2 is given by,

v2 = -(m1÷m2)v1

v2 = -(100÷500)15

v2 = -5 m/s

where the minus sign refers to the direction of cannon's recoil velocity being opposite to that of clown.

Hence, option (4)5.0 m/s is the correct answer.

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3 years ago

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