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KATRIN_1 [288]
4 years ago
12

You have two beakers. One beaker contains 100 mL of NaOH (a strong base); the other contains 100 mL of aqueous Na3PO4 (a weak ba

se). You test the pH of each solution. Which of the following statements is true ?
Chemistry
1 answer:
Ilya [14]4 years ago
6 0

Answer:

D. If the pH of NaOH is 12, then that of Na₃PO₄ solution has to be lesser than 12.

Explanation:

In this problem, we are comparing the pH of a strong base to a weak base. A strong base is one that ionizes completely in aqueous solutions where as a weak base ionizes slightly.

The pH scale is good tool for measuring the acidity and alkalinity of various substances. It ranges from 1 - 14;

   

      1                                      7                                               14

                         ←                                       →

      increasing acidity                          increasing alkalinity

                                        neutrality

Strong bases have their pH value close to 14 and weak bases are close to 7.

Since Na₃PO₄ is a weak base, it will have lesser pH value compared to a strong base such as NaOH

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In naming the compound PCl5, the prefix used with the second element is ____________________.
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Answer:

\boxed {\boxed {\sf Hepta}}

Explanation:

We are given the formula:

PCl_5

This is a molecular formula, because it contains nonmetals.

1. Name the first element

The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.

  • Phosphorous

2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.

  • Phosphorous heptachlorine

Add the ending of -ide.

  • Phosphorous heptachloride

The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.

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eimsori [14]

Answer:

a. Change of state

Explanation:

Because you will see that the state has changed

8 0
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What is potential energy?
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Answer:

A. stored energy

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tiny-mole [99]

Answer:

Check the explanation

Explanation:

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In our universe the ground state electronic configuration of sixth transition metal, Iron (Fe) :  [Ar] 3d^{6} 4s^{2}

and the electronic configuration of seventh transition metal, Cobalt (Co) :  [Ar] 3d^{7} 4s^{2}

=================================

=================================

In universe L there are seven orbitals.

Ground state electronic configuration of sixth and seven transition element.

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Seventh transition metal: [Ar] 3d^{7} 4s^{2}or [X] 3d^{7} 4s^{2}

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