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Stells [14]
2 years ago
5

D. Convert 5.05 x 10-5 ML to hL.

Chemistry
1 answer:
Hitman42 [59]2 years ago
4 0

Answer:

d.5.05*10^-10hl

e.0.45dg

f.7.5*10^5nm

Explanation:

d.1ml=10^-5hl

e.1dg=100000ug

f.1m=1000000000nm

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Which of the following may indicate that a chemical reaction has occurred?
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D, all of the above

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4) express 55mg in kilograms
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The diameter of a hydrogen atom is 106 pm. Find the length in kilometers of a row of 4.34 x 1023 hydrogen atoms?
valina [46]

The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

<h3>Length of the entire hydrogen atoms</h3>

The length of the entire hydrogen atom is calculated as follows;

Length of the row = number x diameter of one

Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²

Length of the row = 4.34 x 10¹⁷ m

Length of the row = 4.34 x 10¹⁴ km

Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

Learn more about diameter of hydrogen atom here: brainly.com/question/13796082

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3 0
2 years ago
A hydrate is compound that included water molecules within its crystal structure. During an experiment to determine the percent
stellarik [79]

Answer:

The percent by mass of water in this crystal is:

  • <u>21.4%</u>

Explanation:

This exercise can be easily solved using a simple rule of three where the initial weight of the hydrated crystal (6,235 g) is taken into account as 100% of the mass, and the percentage to which the mass of 4.90 g corresponds (after getting warm). First, the values and unknown variable are established:

  • 6,235 g = 100%
  • 4.90 g = X

And the value of the variable X is found:

  • X = (4.90 g * 100%) / 6,235 g
  • X = approximately 78.6%.

The calculated value is not yet the percentage of the water, since the water after heating the glass has evaporated, therefore, the remaining percentage must be taken, which can be calculated by subtraction:

  • Water percentage = Total percentage - Percentage after heating.
  • <u>Water percentage = 100% - 78.6% = 21.4%</u>
4 0
3 years ago
Read 2 more answers
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