D. Convert 5.05 x 10-5 ML to hL.

How did the 1964 Alaska earthquake enhance our understanding of Earth's interior?

Travka [436]

<span>Helped confirm the layering of the Earth</span>

3 0

4 years ago

Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 1

blsea [12.9K]

Answer: The maximum amount of water that can be produced is 0.74 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid:}=\frac{1.5g}{36.5g/mol}=0.041mol$

$\text{Moles of sodium hydroxide}=\frac{2.67g}{40g/mol}=0.067mol$

The chemical equation for the reaction is

$HCl+NaOH\rightarrow NaCl+H_2O$

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of NaOH

So, 0.041 moles of HCl will react with = $\frac{1}{1}\times 0.041=0.041mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent. Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of HCl produces = 1 mole of water

So, 0.041 moles of HCl will produce = $\frac{1}{1}\times 0.041=0.041moles$ of water

Mass of water= $moles\times {\text{Molar Mass}}=0.041mol\times 18g/mol=0.74g$

Thus the maximum amount of water that can be produced is 0.74 g

3 0

3 years ago

How many moles of nitrogen monoxide will be generated when 0.83 moles of nitrogen dioxide gas reacts with water?

wel

Answer C) 0.830 moles

Please disgard what I am saying right now, I can't post since it needs 20 characters atleast. I hope this helped! :3

6 0

4 years ago

Read 2 more answers

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179 x 1023 atoms of magnesium with 54.21 g of pho

wlad13 [49]

<h3>Answer:</h3>

18.58 liters of hydrogen gas

<h3>Explanation:</h3>

We are given;

The equation;

3Mg + 2H₃(PO₄) → Mg₃(PO₄)₂ + 3H₂

Atoms of Magnesium = 7.179 x 10^23 atoms
Mass of phosphoric acid as 54.21 g

We are required to determine the volume of hydrogen gas produced;

Step 1; moles of Magnesium

1 mole of an element contains 6.02 × 10^23 atoms

therefore;

Moles of Mg = (7.179 x 10^23 ) ÷ (6.02 × 10^23)

= 1.193 moles

Step 2: Moles of phosphoric acid

moles = Mass ÷ Molar mass

Molar mass of phosphoric acid = 97.994 g/mol

Therefore;

Moles of Phosphoric acid = 54.21 g ÷ 97.994 g/mol

= 0.553 moles

Step 3: Determine the rate limiting reagent

From the mole ratio of Mg to Phosphoric acid (3 : 2);

1.193 moles of magnesium requires 0.795 moles of phosphoric acid while,

0.0553 moles of phosphoric acid requires 0.8295 moles of Mg

Therefore, phosphoric acid is the rate limiting reagent

step 4: Determine the moles of hydrogen produced

From the equation, w moles of phosphoric acid reacts to produce 3 moles of hydrogen;

Therefore; moles of Hydrogen = moles of phosphoric acid × 3/2

= 0.553 moles × 3/2

= 0.8295 moles

Step 5: Volume of hydrogen gas

1 mole of a gas occupies a volume of 22.4 liters at STP

Therefore;

Volume of Hydrogen = 0.8295 moles × 22.4 L/mol

= 18.58 Liters

Therefore; 18.58 liters of hydrogen gas will be produced

4 0

3 years ago

If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess react

jekas [21]

Answer:

5.56g of FeCl2 can be produced

Explanation:

To solve this question we must find the moles of each reactant. With the moles and the chemical equation we can find limiting reactant. With limiting reactant we can find the moles of FeCl2 and its mass as follows:

<em>Moles HCl:</em>

1.5L * (0.25mol / L) = 0.375 moles HCl

<em>Moles Fe -Molar mass: 55.845g/mol-</em>

2.45g * (1mol / 55.845g) = 0.0439 moles Fe

For a complete reaction of 0.375 moles HCl are needed:

0.375 moles HCl * (1mol Fe / 2mol HCl) = 0.1875 moles Fe

As there are just 0.0439 moles Fe, <em>Fe is limiting reactant</em>

<em />

1mol of Fe produce 1 mole of FeCl2, 0.0439 moles Fe produce 0.0439 moles of FeCl2. The mass is:

<em>Mass FeCl2 -Molar mass: 126.751g/mol:</em>

0.0439 moles Fe * (126.751g / mol) =

<h3>5.56g of FeCl2 can be produced</h3>

5 0

3 years ago